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3 years ago

What is the equation of a horizontal line that goes through the coordinate (4,-2)

Mathematics

1 answer:

olchik [2.2K]3 years ago

5 0

The equation will be:

y = -2

Step-by-step explanation:

A horizontal line has no slope as it is parallel to x-axis.

The horizontal line is in the form y = b where b is the y-intercept.

Given

The line passes through (4 -2).

The y-coordinate of the given point is -2 which means that the line will intersect the y-axis on -2

So,

b = -2

and

The equation will be:

y = -2

Keywords: Equation of line, slope

Learn more about equation of line at:

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Find the sum of the interior angles of a regular 14-gon.

Ira Lisetskai [31]

9514 1404 393

Answer:

2160°

Step-by-step explanation:

The sum of interior angles of a convex n-gon is ...

angle sum = 180(n -2)°

When n=14, the angle sum is ...

angle sum = 180(14 -2)° = 2160°

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2 years ago

Find the value -2/3÷ 4/6. A -1 B 4/9 C -9/4 D 1

Allushta [10]

Answer should be -1

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2 years ago

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PLEASE HELP ASAP!!!

Elan Coil [88]

Answer:

The number is 5

Step-by-step explanation:

6+3n = 5n-4

Subtract 3n from each side

6+3n-3n = 5n-3n-4

6 = 2n-4

Add 4 to each side

6+4 = 2n-4+4

10= 2n

Divide by 2

10/2 =2n/2

5=n

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3 years ago

I WILL MARK BRAINLIST!!

Soloha48 [4]

Answer:

For $(2x^2 + 8x - 8)$ , the group is CLOSED as it a polynomial.

Step-by-step explanation:

Here, the given polynomials are:

$P(x)=(5x^2+2x-6)\\Q(x)=(3x^2-6x+2)$

Now, a group G is said to be CLOSED UNDER SUBTRACTION if,

a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G

Now, here:

$R(x) = P(x) - Q(x) = (5x^2+2x-6) - (3x^2-6x+2) = (2x^2 + 8x - 8)$

or, $R(x) = (2x^2 + 8x - 8)$

Also, R(x) is a POLYNOMIAL.

So, R(x) is an Element of group G.

So, the set G of polynomials.

Hence, for the polynomial $(2x^2 + 8x - 8)$ , it will be a polynomial the group is CLOSED.

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3 years ago

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Select the correct answer from the drop-down menu. A=-2[-6 4, 3 7, 12 10], B=3[-2 2 8, 8 5 6], 3C=3[-2 8, 2 5, 8 6] and D=-1[-12

max2010maxim [7]

Answer:

A and D are equal

Step-by-step explanation:

Given

$A=-2[-6, 4, 3 ,7, 12, 10]$

$B=3[-2, 2, 8, 8, 5, 6]$

$3C=3[-2, 8, 2, 5, 8, 6]$

$D=-1[-12, 8, 6, 14, 24, 20].$

Required

The equal matrices

First, we simplify the given expressions

$A=-2[-6, 4, 3 ,7, 12, 10]$

Open bracket

$A= [12, -8, -6 ,-14, -24, -20]$

Next:

$B=3[-2, 2, 8, 8, 5, 6]$

Open bracket

$B=[-6, 6, 24, 24, 15, 18]$

Next:

$3C=3[-2, 8, 2, 5, 8, 6]$

Divide by 3

$C=[-2, 8, 2, 5, 8, 6]$

Lastly:

$D=-1[-12, 8, 6, 14, 24, 20].$

Open bracket

$D=[12, -8, -6, -14, -24, -20].$

By comparison:

$A = D=[12, -8, -6, -14, -24, -20].$

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2 years ago