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qwelly [4]
2 years ago
8

HELP I NEED HELP ASAP

Mathematics
1 answer:
aleksandrvk [35]2 years ago
6 0

Answer:

I cannot see the picture

Step-by-step explanation:

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The triangle shown in the graph is transformed by matrix R. Plot the resulting triangle.
DerKrebs [107]

Answer:

I cant Im sorry

Step-by-step explanation:

5 0
2 years ago
Whatsthe defenition of hypotenuse
marta [7]
Hypotenuse is the longest side of a right triangle. It is equal to the sum of the squares on the other two sides.
8 0
3 years ago
EXAMPLE 1 (a) Find the derivative of r(t) = (2 + t3)i + te−tj + sin(6t)k. (b) Find the unit tangent vector at the point t = 0. S
Tatiana [17]

The correct question is:

(a) Find the derivative of r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(b) Find the unit tangent vector at the point t = 0.

Answer:

The derivative of r(t) is 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is (j/2 + 3k)

Step-by-step explanation:

Given

r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(a) To find the derivative of r(t), we differentiate r(t) with respect to t.

So, the derivative

r'(t) = 3t²i +[e^(-t) - te^(-t)]j + 6cos(6t)k

= 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is obtained using the formula r'(0)/|r(0)|. r(0) is the value of r'(t) at t = 0, and |r(0)| is the modulus of r(0).

Now,

r'(0) = 3t²i + (1 - t)e^(-t)j + 6cos(6t)k; at t = 0

= 3(0)²i + (1 - 0)e^(0)j + 6cos(0)k

= j + 6k (Because cos(0) = 1)

r'(0) = j + 6k

r(0) = (2 + t³)i + te^(−t)j + sin(6t)k; at t = 0

= (2 + 0³)i + (0)e^(0)j + sin(0)k

= 2i (Because sin(0) = 0)

r(0) = 2i

Note: Suppose A = xi +yj +zk

|A| = √(x² + y² + z²).

So |r(0)| = √(2²) = 2

And finally, we can obtain the unit tangent vector

r'(0)/|r(0)| = (j + 6k)/2

= j/2 + 3k

8 0
3 years ago
Convert y=-1.4x+9.6 to standard form
pychu [463]

Answer:

14x-10y=-96

Step-by-step explanation:

we know that

The equation of the line in standard form is equal to

Ax+By=C

where

A is a positive integer

B and C are integers

so

we have

y=1.4x+9.6

Multiply by 10 both sides

10y=14x+96

isolate the variable x and y (Remember that A must be positive)

14x-10y=-96 -----> standard form

6 0
3 years ago
3) How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution? (25,15)THATS
serg [7]
<span>let x = the number of liters of the 20% solution. 

let y = the number of liters of the 60% solution. 

you want x + y to be equal to 40 liters. 

x is the number of liters total in the first solution.
y is the number of liters total in the second solution. 

you want .2 * x + .6 * y to be equal to .35 * 40 

.2 * x is the number of liters of acid in the first solution.
.6 * y is the number of liters of acid in the second solution.
.35 * 40 is the number of liters of acid in the final solution. 

you have two equations that need to be solved simultaneously. 

they are: 

x + y = 40
.2x + .6y = .35*40 

simplify these equations to get: 


x + y = 40
.2x + .6y = 14 

you can solve by substitution or by elimination or by graphing.
i will solve this one by graphing.
this means to graph both equations and find the intersection. 

the graph looks like this: 

 
the graph says the intersection is at the coordinate point of (25,15). 

this means that x = 25 and y = 15. 

x is the number of liters of the 20% solution.
y is the number of liters of the 60% solution. 

the formula of .2x + .6y = 14 becomes .2 * 25 + .6 * 15 = 14.
simplify this equation to get 14 = 14.
this confirms the solution is good. 
</span>
8 0
3 years ago
Read 2 more answers
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