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Yuri [45]
3 years ago
14

Days of the week are represented as three-letter strings ("Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"). Write a javaScript f

unction solution that, given a string S representing the day of the week and an integer K (between 0 and 500), returns the day of the week that is K days later. For example, given S = "Wed" and K = 2, the function should return "Fri". Given S = "Sat" and K = 23, the function should return "Mon".
Computers and Technology
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

function getDay(s, k){

var weekDays = ["Mon","Tue","Wed","Thu","Fri","Sat","Sun"];

var index=weekDays.findIndex(function(weekDay){return weekDay==s;});

return weekDays[(index+k)%7];

}

Explanation:

//this functions receive the next parameters:

//s which is the day of the week

//k the number of days after s week day

function getDay(s, k){

var weekDays = ["Mon","Tue","Wed","Thu","Fri","Sat","Sun"];

//variable index is the index in list weekDays of s

var index=weekDays.findIndex(function(weekDay){return weekDay==s;});

//use module operator % to get the remainder of the division (index+k)/7

//return the string value of the day

return weekDays[(index+k)%7];

}

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Write the Flowchart to find Even number between 1 to 50<br>​
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Answer:

See attachment for flowchart

Explanation:

Required

Flowchart to fine even from 1 to 50

The flowchart has been attached.

The rough algorithm (explanation) of the flowchart is as follows.

1. Start

2. Initialize num to 1

3. Check if num is less than or equal to 50

  3.1 If yes

      3.1.1 Check if num is even

      3.1.1.1 If yes

         3.1.1.2 Print num

  3.1.3 Increase num by 1

 3.2 If num is greater than 50

    3.2.1 Stop

4. Goto 3

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Interest assessments are always accurate. True False
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Answer:

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Explanation:

3 0
3 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
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