Answer:
e
Step-by-step explanation:
e im not sure
-10-2•14a it should be something like this
Answer: 3 x 6
18 yd²
Step-by-step explanation:
Step-by-step explanation:
![\tt{ \frac{x}{2} - \frac{x}{5} = 2}](https://tex.z-dn.net/?f=%20%20%5Ctt%7B%20%5Cfrac%7Bx%7D%7B2%7D%20%20%20-%20%20%5Cfrac%7Bx%7D%7B5%7D%20%20%3D%202%7D)
Take the L.C.M of 2 & 5. It's ' 10 '. Firstly find out the factors of 2 [ i.e 1 × 2 ] and then secondly find out the factors of 5 [ i.e 1 × 5 ]. Now , Note that while finding L.C.M of any numbers, Common numbers & Remaining numbers must be multiplied. In our case , common number = 1 & Remaining numbers are 2 & 5. Multiply them : [ 1 × 2 × 5 = 10 ].
⟶ ![\tt{ \frac{x \times 5 - x \times 2}{10} = 2}](https://tex.z-dn.net/?f=%20%5Ctt%7B%20%5Cfrac%7Bx%20%5Ctimes%205%20-%20x%20%5Ctimes%202%7D%7B10%7D%20%20%3D%202%7D)
⟶ ![\tt{ \frac{5x - 2x}{10} = 2}](https://tex.z-dn.net/?f=%20%5Ctt%7B%20%5Cfrac%7B5x%20-%202x%7D%7B10%7D%20%20%3D%202%7D)
Subtract 2x from 5x :
⟶ ![\tt{ \frac{3x}{10} = 2}](https://tex.z-dn.net/?f=%20%5Ctt%7B%20%5Cfrac%7B3x%7D%7B10%7D%20%20%3D%202%7D)
Apply cross product property :
⟶ ![\tt{3x \times 1 = 2 \times 10}](https://tex.z-dn.net/?f=%20%5Ctt%7B3x%20%5Ctimes%201%20%3D%202%20%5Ctimes%2010%7D)
⟶ ![\tt{3x = 20}](https://tex.z-dn.net/?f=%20%5Ctt%7B3x%20%3D%2020%7D)
Here, We have to think about how to remove the coefficient 3. For that , Divide both sides of the equation by 3.
⟶ ![\tt{ \frac{3x}{3} = \frac{20}{3}}](https://tex.z-dn.net/?f=%20%5Ctt%7B%20%5Cfrac%7B3x%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7B20%7D%7B3%7D%7D%20)
⟶ ![\tt{x =6.67}](https://tex.z-dn.net/?f=%20%5Ctt%7Bx%20%3D6.67%7D)
![\pink {\boxed{ \boxed{ \tt{⇾ Our \: final \: answer : \boxed{ \underline{ \tt{x = \frac{20}{3} \: or \: 6.67 }}}}}}}](https://tex.z-dn.net/?f=%20%5Cpink%20%7B%5Cboxed%7B%20%5Cboxed%7B%20%5Ctt%7B%E2%87%BE%20Our%20%5C%3A%20final%20%5C%3A%20answer%20%3A%20%20%5Cboxed%7B%20%5Cunderline%7B%20%5Ctt%7Bx%20%3D%20%20%5Cfrac%7B20%7D%7B3%7D%20%20%5C%3A%20or%20%5C%3A%206.67%20%7D%7D%7D%7D%7D%7D%7D)
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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Answer:
The width is ![6x^2](https://tex.z-dn.net/?f=6x%5E2)
Step-by-step explanation:
The area of a rectangle is given as : ![Area=l\times w](https://tex.z-dn.net/?f=Area%3Dl%5Ctimes%20w)
This implies that: ![w=\frac{Area}{l}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7BArea%7D%7Bl%7D)
We have that the length is
and the area is ![Area=24x^4+72x^3](https://tex.z-dn.net/?f=Area%3D24x%5E4%2B72x%5E3)
We substitute to get:
![w=\frac{24x^4+72x^3}{4x^2+12x}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B24x%5E4%2B72x%5E3%7D%7B4x%5E2%2B12x%7D)
![\implies w=\frac{24x^2(x^2+3x)}{4(x^2+3x)}](https://tex.z-dn.net/?f=%5Cimplies%20w%3D%5Cfrac%7B24x%5E2%28x%5E2%2B3x%29%7D%7B4%28x%5E2%2B3x%29%7D)
We cancel out the common factors to get:
![w=6x^2](https://tex.z-dn.net/?f=w%3D6x%5E2)