1.2
0.67
5/8
3.5
I think this is what it would be.
81.5%
i honestly looked at the numbers in the problem
1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207
Oh that’s on safari i just looked it up lol. go check it out. sorry if it’s not there for u. but i didn’t feel like typing that much
Answer:
x = 20
Length = 20ft
Width = 12ft
Step-by-step explanation:
A = 240
x^2 - 8x = 240
x^2 - 8x - 240 = 0
x^2 - 20x + 12x - 240 = 0
x(x-20) + 12(x-20) = 0
(x+12)(x-20) = 0
x = 20
x = -12 (which we discard since x is a length)
So the dimensions are 20ft and 20-8 = 12ft
