It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
x = 28
Step-by-step explanation:
If the quadrilaterals are similar, there is a proportionality among their sides:
The top side in the large figure (70) is to the top side in the small figure (10) in the same ratio as the left side (x) in the large figure is to the left side in the small figure (4). This in math terms is written as:
We can then solve for the unknown "x" by multiplying both sides by 4:
There's no way for me to do that, because my expression
is totally blank, and doesn't involve ' m ' in any way.
But if you'll come back and give us <u>your</u> expression, I'll
evaluate it for m=12, and I'll also show you how.
Answer:
the space (usually measured in degrees) between two intersecting lines or surfaces at or close to the point where they meet.
Answer:
No, it is a reflection and a translation
Step-by-step explanation:
It reflects off of A and translates to the right over B
