The answer is A.
When creating a business budget, include all you income sources and ad both fixed and variable costs and expenses.
The first and most important element of a good business budget is to tally and figure out your income sources. Income sources include things like product sales, earnings, and others. You should also be able to determine the fixed costs and include variable expenses. Variable expenses are those items that do not have a fixed price tag and may include raw materials, commissions, advertising, transportation, printing services, and many others.
Answer:
Explanation:
A general idea is that you should repeat the simulation until the results converge. An easy but illustrative example of this is that we want to see if the R function rbinom is accurate in simulating a coin toss with a given probability. We will simulate one coin toss 10000 times, and plot the percentage of heads against the number of coin tosses:
set.seed(1)
n <- 10000
result <- NULL
percent <- NULL
for (i in 1:n) {
result[i] <- rbinom(1,1,0.5)
percent[i] <- sum(result)/i
}
plot(seq(1:10000),percent, type="l")
abline(0.5, 0, lty=2)
A proxy server is a server that intercepts user requests from the internal secure network and then processes that request on behalf of the user.
The proxy server can be a computer or application program<span> that gets the requests from clients and seeks resources from other </span>servers. It is a <span>intermediary point between the end user and the backbone network.</span>
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
