1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djyliett [7]
3 years ago
11

Write a program that prompts the user for the name of two files each containing a single line that represents a decimal integerc

all them m and n, keep in mind that theseintegerscould be very largein absolute value, so they might not be stored neither as along nor intvariables. You should:a)Handle erroneous input graciously.b)Include a class named BigIntegerwhere you define an integer as a linked list, along with integer operations such as addition and subtraction [multiplication and division will grant you extra points] c)Test your program for each operation and store the result of each operation as a single decimal number in a separate file containing only one line\
Computers and Technology
1 answer:
storchak [24]3 years ago
4 0

Answer:

The output is seen bellow

Explanation:

public class BigInteger {

  public class Node{

      private char data;

      private Node next;

      public Node(char d){

          this.setData(d);

          this.setNext(null);

      }

      public char getData() {

          return data;

      }

      public void setData(char data) {

          this.data = data;

      }

      public Node getNext() {

          return next;

      }

      public void setNext(Node next) {

          this.next = next;

      }      

  }

 

  private Node root;

 

  public BigInteger(String s){

      this.root=null;

     

      for(int i=s.length()-1;i>=0;i--){

          Node node=new Node(s.charAt(i));

          node.setNext(root);

          root=node;

      }

  }

 

  public String toString(){

      String str="";

      Node cur=this.root;

      int i=0;

     

      while(cur!=null){

          if(i==0 && cur.getData()=='0'){

             

          }

          else{

              i=1;

              str+=cur.getData();

          }

         

          cur=cur.getNext();

      }

     

      return str;

  }

 

  public String reverse(String s){

      String ret="";      

      for(int i=s.length()-1;i>=0;i--){

          ret+=s.charAt(i);

      }      

      return ret;

  }

 

  public BigInteger add(BigInteger s){

      String f=this.reverse(this.toString());

      String l=this.reverse(s.toString());

      int max=(f.length()>l.length())?f.length():l.length();

     

      String ret="";

     

      int carry=0;

     

      for(int i=0;i<max;i++){

          int sum=carry;

          if(i<f.length()){

              sum+=(f.charAt(i)-'0');

          }

          if(i<l.length()){

              sum+=(l.charAt(i)-'0');

          }

          ret+=(char)(sum%10+'0');

          carry=(sum/10);

      }

      if(carry!=0){

          ret+='1';

      }

     

      BigInteger bi=new BigInteger(this.reverse(ret));

      return bi;

  }

  public boolean bigNum(String s1,String s2){

             

      if(s1.length()>s2.length()){

          return true;

      }

      else{

          if(s1.length()<s2.length()){

              return false;

          }

          else{

              for(int i=0;i<s1.length();i++){

                  if(s1.charAt(i)!=s2.charAt(i)){

                      if(s1.charAt(i)>s2.charAt(i)){

                          return true;

                      }

                      else{

                          return false;

                      }

                  }

              }                  

          }

      }

      return false;

  }

 

  public BigInteger subtraction(BigInteger s){

      String f=this.toString();

      String l=s.toString();

     

      boolean b=this.bigNum(f, l);

   

      if(b==false){

          String tmp=f;

          f=l;

          l=tmp;

      }

     

      f=this.reverse(f);

      l=this.reverse(l);

     

      int max=(f.length()>l.length())?f.length():l.length();

     

      String ret="";

     

      int borrow=0;

     

      for(int i=0;i<max;i++){

          int sum=borrow;

          if(i<f.length()){

              sum+=(f.charAt(i)-'0');

          }

          if(i<l.length()){

              sum-=(l.charAt(i)-'0');

          }

          if(sum<0){borrow=-1;sum=10+sum;}

          else{borrow=0;}

         

          ret+=(char)(sum%10+'0');

      }

     

      if(b==false){

          ret+="-";

      }

     

      BigInteger bi=new BigInteger(this.reverse(ret));

      return bi;

  }

 

  public BigInteger multiplication(BigInteger s){

      String f=this.toString();

      String l=s.toString();

 

      int len=l.length();

     

      BigInteger bi=new BigInteger("");

      for(int i=len-1;i>=0;i--){

          //System.out.println(l.charAt(i));

          BigInteger r=new BigInteger(f);

          for(int j=(l.charAt(i)-'0');j>1;j--){

              r=r.add(new BigInteger(f));

              //System.out.print(r+" " );

          }

          //System.out.println();

          bi=bi.add(r);

          f=f+"0";

      }

      return bi;

  }

 

  public BigInteger division(BigInteger s){

      BigInteger t=this;

      BigInteger bi=new BigInteger("");

      int i=0;

      t=t.subtraction(s);

      String str=t.toString();

     

      while(str.charAt(0)!='-' && i<40){

          //System.out.println(str+" "+(i+1));

          bi=bi.add(new BigInteger("1"));

          t=t.subtraction(s);

          str=t.toString();  

         

          i++;

      }

      return bi;    

  }  

}  

-------------------

import java.io.BufferedReader;

import java.io.FileNotFoundException;

import java.io.FileReader;

import java.io.FileWriter;

import java.io.IOException;

import java.io.PrintWriter;

import java.util.Scanner;

public class Driver {

  public static void main(String [] args){

      Scanner sc=new Scanner(System.in);

     

      String str1="";

      String str2="";

     

      System.out.print("Enter file name 1 :");

      String file1=sc.next();

      //String file1="datafile1.txt";

      BufferedReader reader1;

      try {

          reader1 = new BufferedReader(new FileReader(file1));

          while((str1=reader1.readLine())!=null){

              break;

          }

          reader1.close();

      } catch (FileNotFoundException e) {

          // TODO Auto-generated catch block

          e.printStackTrace();

      } catch (IOException e) {

          // TODO Auto-generated catch block

          e.printStackTrace();

      }

 

      System.out.print("Enter file name 2 :");

      String file2=sc.next();

      //String file2="datafile2.txt";

      BufferedReader reader2;

      try {

          reader2 = new BufferedReader(new FileReader(file2));

          while((str2=reader2.readLine())!=null){

              break;

          }

          reader2.close();

      } catch (FileNotFoundException e) {

          // TODO Auto-generated catch block

          e.printStackTrace();

      } catch (IOException e) {

          // TODO Auto-generated catch block

          e.printStackTrace();

      }

You might be interested in
Assume that success is a variable of type boolean that has been declared. Assume that processor refers to an object that provide
Iteru [2.4K]
Try {
AutoFactory.shutdown();
} catch (ProductionInProgressException e) {
AutoFactory.reset();
}
6 0
3 years ago
The 3rd generation programming language that most students learned when most computers used MS DOS was ___ . It remains a safe p
Diano4ka-milaya [45]

Answer:

Basic

Explanation:

The 3rd generation programming language that most students learned when most computers used MS DOS was basic. It remains a safe programming language for using 3rd party code and provides a coding standard that integrates easily with other programming languages.

7 0
3 years ago
When Windows deletes the driver package and driver files, in what situation might it not delete driver files used by the device
musickatia [10]

Answer:

when there is no junk

Explanation:

3 0
3 years ago
A contiguous subsequence of a list S is a subsequence made up of consecutive elements of S. For example, if S is 5,15,-30,10,-5,
Sindrei [870]

Answer:

We made use of the dynamic programming method to solve a linear-time algorithm which is given below in the explanation section.

Explanation:

Solution

(1) By making use of the  dynamic programming, we can solve the problem in linear time.

Now,

We consider a linear number of sub-problems, each of which can be solved using previously solved sub-problems in constant time, this giving a running time of O(n)

Let G[t] represent the sum of a maximum sum contiguous sub-sequence ending exactly at index t

Thus, given that:

G[t+1] = max{G[t] + A[t+1] ,A[t+1] } (for all   1<=t<= n-1)

Then,

G[0] = A[0].

Using the above recurrence relation, we can compute the sum of the optimal sub sequence for array A, which would just be the maximum over G[i] for 0 <= i<= n-1.

However, we are required to output the starting and ending indices of an optimal sub-sequence, we would use another array V where V[i] would store the starting index for a maximum sum contiguous sub sequence ending at index i.

Now the algorithm would be:

Create arrays G and V each of size n.

G[0] = A[0];

V[0] = 0;

max = G[0];

max_start = 0, max_end = 0;

For i going from 1 to n-1:

// We know that G[i] = max { G[i-1] + A[i], A[i] .

If ( G[i-1] > 0)

G[i] = G[i-1] + A[i];

V[i] = V[i-1];

Else

G[i] = A[i];

V[i] = i;

If ( G[i] > max)

max_start = V[i];

max_end = i;

max = G[i];

EndFor.

Output max_start and max_end.

The above algorithm takes O(n) time .

4 0
2 years ago
associate true with the variable has_dups if the list list1 has any duplicate elements (that is if any element appears more than
nordsb [41]

True. If the list contains any elements that appear more than once, then it has duplicate elements and the variable has_dups is True.

What is variable?
Throughout computer programming, a variable is indeed a named container for a specific set of bits or type of data. A variable is indeed an abstract storage location with an associated symbolic name that holds some unidentified quantity of information made reference to as a value. Eventually, a memory address may be used to link or identify a variable. In addition to using the variable name or the variable itself, depending on circumstances, the stored value is typically referenced by the variable name. The name can be used independently of the precise information it represents thanks to the separation of name as well as content. During run time, a value can be bound to an identification number in computer source code.

To learn more about variable
brainly.com/question/29360094
#SPJ1

7 0
1 year ago
Other questions:
  • A ________ is a system of hardware and software that stores user data in many different geographical locations and makes that da
    14·1 answer
  • The term integration refers to the ability to
    6·1 answer
  • How can i become an ailen?
    5·2 answers
  • Of the sequences listed below, which shows the correct order of the steps in the incident management workflow: (1) authenticate
    14·1 answer
  • Why won't Brainly let me send a link? This is just du*mb! I want to send good articles explaining a content, and this site just
    5·1 answer
  • Mary works for a multimedia firm, and she spends long hours on a desktop computer. Recently, she expired back pain and visited h
    12·1 answer
  • Which of the following is an example of an output device
    13·1 answer
  • Which of the following are acceptable to share? Check all of the boxes that apply.
    13·1 answer
  • when inserting a bibliography one choose from multiple ______ of bibliographies.[insert Bibliography]
    12·1 answer
  • each data mining technique has its advantages and limitations. which data mining technique mimics the neural structure of the br
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!