The segment is 8 units long
0.373 seconds. First, calculate the initial vertical velocity of the shell. 800sin(30) = 800*0.5 = 400 m/s Now the formula for the distance traveled is d = 400 m/s * T + 0.5A T^2 Substituting known values gives. 150 = 400 m/s * T + 0.5*9.80m/s^2 T^2 150 = 400 m/s * T + 4.9 m/s^2 T^2 Arrange as a quadratic formula 0 = 400 m/s * T + 4.9 m/s^2 T^2 - 150 4.9 m/s^2 T^2 + 400 m/s * T - 150 = 0 Now solve for T using the quadratic formula with a=4.9, b=400, and c=-150 The calculated value is 0.373 seconds. Is this value reasonable? Let's check. The initial downward velocity is 400 m/s. So 150/400 = 0.375 seconds. Since the actual time will be a bit less due to acceleration by gravity and since the total time is so short, there won't be much acceleration due to gravity, the value of 0.373 is quite reasonable.
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Answer:
-12
Step-by-step explanation:
The average rate of change of a function f(x) on an interval [a, b] is defined as ...
average rate of change = ((f(b) -f(a))/(b -a)
For the given function and interval, this is ...
average rate of change = (f(1.25) -f(0.75))/(1.25 -0.75)
= (4 -10)/(0.5) = -12
The average rate of change is -12 on the interval.
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The calculator results for f(1.25) and f(0.75) are shown in the attachment, along with the computation of the average rate of change.
Answer:
Uh...I think you forgot about the actaul question. But I'm gonna say Brady cause why not
Answer:
x=-5
Step-by-step explanation: