Question

Plz help ASAP WILL MARK BRAINLIST

Answer 1

Answer: B. The domain is {x|x<0 or x>0} and the range is {y|y>0}

Step-by-step explanation:

f(x)=x^-2

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#1 Any negative (-) exponents means the answer will be 1/ the term

- for example, 3^-2=1/3^2=1/9

NOTE: NEGATIVE EXPONENTS DOES NOT MEAN IT IS A NEGATIVE NUMBER, IT IS STILL A POSITIVE NUMBER IF THE BASE IS POSITIVE.

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The domain, which will be the value of x.

x can be any real number, except 0, because 0 can't go to negative exponents or else it will be undefined.

{x|x<0 or x>0}

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The range, which will be the value of y.

Since the x value is being squared, it is always positive

{y|y>0}

Answer 2

Answer:

A. The first choice.

Step-by-step explanation:

$f(x) = x^{-2}$

Let's rewrite the function in a more familiar way.

$f(x) = \dfrac{1}{x^2}$

Domain:

We know that a denominator cannot equal zero, so we set the denominator equal to zero to find the values of x that must be excluded from the domain.

x^2 = 0

x = 0

The only value excluded from the domain is x = 0.

The domain is all reals except for zero.

Range:

Now that we know the domain is all real numbers except for 0, we look closely at the denominator.

What happens when you replace x with negative numbers? Since you are squaring x, all denominators will be positive. When you replace x with positive numbers, all denominators will also be positive. For values of x with a large absolute value, for example 1000, -1000, 1,000,000 or -1,000,000, as the absolute value of x increases, f(x) approaches zero. For values of x with a small absolute value, such as 0.0001, -0.0001, -0.00000001, or 0.00000001, as x approaches zero, f(x) approaches positive infinity.

The range is all positive real numbers.

Answer:

Domain: all real numbers except 0.

Range: all positive real numbers.