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slava [35]
3 years ago
10

Cassidy wants to divide 4x^2−2x+3 by x + 2 using synthetic division.

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer: <em>You didn't provide the options so unable to know which option is the correct answer</em>

<u>Step-by-step explanation:</u>

x + 2 = 0   ⇒   x = -2

-2   |  4      -2       3

     <u>|   ↓     -8      20 </u>

         4     -10     23

(x + 2)(4x - 10 + \frac{23}{x+2})

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What is the solution to this equation: 5x to the 2 power - 36x - 81 = ?
Viefleur [7K]

Answer:

5x² - 36x - 81

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Combining Like Terms
  • Standard Form: ax² + bx + c = 0

Step-by-step explanation:

<u>Step 1: Define expression</u>

5x² - 36x - 81

<u>Step 2: Simplify</u>

<em>We cannot simplify the expression down further.</em>

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Allushta [10]
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Find the length of the third side of the triangle
Lana71 [14]

PYTHOGOROS THEROEM :-

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8 0
3 years ago
keesha earns $350 a week working in a clothing store. As a bonus, her employer pays $15 more than she earned the previous week,
patriot [66]
I got 455 at the 10th week
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8 0
3 years ago
PLEASEE HELP I WILL GIVE A BRAINLY
Genrish500 [490]

Answer:

a) 7x words

b) 1000/x days

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Step-by-step explanation:

The best way to do this would be to plug in real numbers to see how each situation would play out.  For example, for part a, let's say he learns 20 new words each day.  One week has seven days, so that would be 20 x 7, which is 140 words.  You multiply the # of days by the # of words, which is x.

For part b, if he tried to reach 1000 new words by doing 20 new words a day, you would find how long that would take by doing 1000 / 20, which would give you 500 days.  You divide the # of new words he's trying to reach by the # of words a day.

For part c, he already has a set # of new words that he's learned, and now he's just continuing the progress, so you start out with 15000, then add that to 10 new words a day multiplied by # of days (x).

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3 years ago
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