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lana [24]
3 years ago
5

For a hypothesis test of H0: p = 0.35 against the alternative Ha: p > 0.35, the z test statistic is found to be 2.45. What ca

n be said about this finding?
Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

From this finding, it can be said that the sample proportion is greater than the population proportion because the test statistic (z = 2.45) is positive.

Step-by-step explanation:

H0: p = 0.35

Ha: p > 0.35

The test is a one-tailed test because the alternate hypothesis is expressed using greater than.

The test statistic (z) for a proportion is given as (p' - p) ÷ sqrt [p(1-p)/n]

p' is sample proportion

p is population proportion

n is sample size

For the test statistic z to be positive, p' must be greater than p.

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A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
3 years ago
Y = -8x – 3<br> x+y=7<br> Is (3, 4) a solution of the system?
77julia77 [94]
4 = -8(3) - 3
4 = -24-3 false

3 + 4 = 7 true

The first one is false, second is true
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3 years ago
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Every year, Calaveras County holds a frog jumping contest. Mia entered her frog into the 100-yard contest and it completed the r
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Answer:

Step-by-step explanation:

For Mia:

distance,d = 100 yard

time, t = 2 min 33 sec = 153 s

Speed = distance / time

speed = 100 / 153 = 0.65 yard/s

For Larisa:

distance, d = 350 yard

time, t = 5 min 18 sec = 318 s

speed = 350 / 318 = 1.1 yard/s

So, the speed of Larisa is more than the speed of Mia.

7 0
3 years ago
Versity City Geometry 1.2 - CR (9/17)
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Answer:

(x+3)^{2}+(y+5)^{2}=36

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

In this problem we have

(h,k)=(-3,-5)

r= 6\ units

substitute

(x+3)^{2}+(y+5)^{2}=6^{2}

(x+3)^{2}+(y+5)^{2}=36

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