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lana [24]
3 years ago
5

For a hypothesis test of H0: p = 0.35 against the alternative Ha: p > 0.35, the z test statistic is found to be 2.45. What ca

n be said about this finding?
Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

From this finding, it can be said that the sample proportion is greater than the population proportion because the test statistic (z = 2.45) is positive.

Step-by-step explanation:

H0: p = 0.35

Ha: p > 0.35

The test is a one-tailed test because the alternate hypothesis is expressed using greater than.

The test statistic (z) for a proportion is given as (p' - p) ÷ sqrt [p(1-p)/n]

p' is sample proportion

p is population proportion

n is sample size

For the test statistic z to be positive, p' must be greater than p.

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lisabon 2012 [21]
For the first problem, the answer is D, because every year, the graph goes down by about $4,500.
For problem two, 
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I'm unsure about b and c but I hope I helped with the others!
3 0
3 years ago
a horse weight decreases by 1/2 pound per week at this rate how many weeks will it take for the horse to visit total of 5 1/2 wr
kykrilka [37]

Answer:

11 weeks

Step-by-step explanation:

5÷1/2=10

10+1=11

Sorry if I'm wrong

4 0
2 years ago
Read 2 more answers
If H= 2f over m+1, solve the equation for f
Viefleur [7K]
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2

3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4

3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
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8 0
2 years ago
Galileo wanted to release a wooden ball and an iron ball from a height of 100 meters and measure the duration of their fall. He
kotegsom [21]

<u><em>Answer:</em></u>

He would need to climb 480.97 m

<u><em>Explanation:</em></u>

The ground, the plane to climb and the altitude (100 m) all form a right-angled triangle

Therefore, we can apply the special trig functions.

<u>These functions are as follows:</u>

sin(θ) = \frac{opposite}{hypotenuse}

cos(θ) = \frac{adjacent}{hypotenuse}

tan(θ) = \frac{opposite}{adjacent}

<u>From the diagram, we have:</u>

θ = 12°

The distance that he needs to climb is the hypotenuse

The altitude = 100 m is the opposite

<u>Therefore, we can use the sin function as follows:</u>

sin(12°) = \frac{100}{hypotenuse}

hypotenuse = \frac{100}{sin(12)}

hypotenuse = 480.97 meters to the nearest hundredth

Therefore, he would need to climb 480.97 meters

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

8 0
2 years ago
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