All categories

3 years ago

What is the missing statement for step 6? m∠SQV + m∠VQT = 180° m∠SQV + m∠SQT = m∠VQT m∠SQV + m∠SQT = 180° m∠VQT + m∠ZRS = 180°

Mathematics

1 answer:

salantis [7]3 years ago

3 0

Answer:

D. m∠VQT + m∠ZRS = 180°

Step-by-step explanation:

I just took and got it correct on the quiz.

You might be interested in

Y2-y1

defon

Answer:

$\sf m=\dfrac{1}{3}$

Step-by-step explanation:

The slope of a line can be found using the following formula:

$\sf m=\dfrac{y_2-y_1}{x_2-x_1}$

Given the points (1, 5) and (4, 6):

<u>where:</u>

x₁ = 1, x₂ = 4

y₁ = 5, y₂ = 6

Substitute these values into the formula:

$\sf \sf m=\dfrac{y_2-y_1}{x_2-x_1}\\\\m=\dfrac{6-5}{4-1}\\\\m=\dfrac{1}{3}$

Learn more here:

brainly.com/question/27781455
brainly.com/question/19708647

3 0

2 years ago

Divide. Show your work.<br><br> (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

4 years ago

Given the parent function f(x)=x^3 give the best description of the graph of y=x^3+3 .

umka21 [38]

The correct answer is A. +3, unless inside parentheses, indicates a positive vertical change, thus the function would move upward. If the function looked like 2(x^3 + 3) the change from the +3 would be horizontal (left) instead.

4 0

3 years ago

Someone please help

OleMash [197]

Answer:

Why wont anyone help me please

4 0

3 years ago

An acrobat was launched toward a water tank, with an upward velocity of 48 feet per second. The launch point was 32 feet below t

ludmilkaskok [199]

Hello. How are you. Do u take K12

3 0

4 years ago