3 years ago

18 lb3 oz + 25 lb5 oz

Mathematics

1 answer:

Jlenok [28]3 years ago

6 0

43lb 8oz add them like normal #'s

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Given that cos (x) = 1/3, find sin (90 - x)

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Answer:

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Step-by-step explanation:

Given: $\cos (x)=\frac{1}{3}$

We have to find the value of $\sin(90^{\circ} - x)$

Since Given $\cos (x)=\frac{1}{3}$

Using trigonometric identity,

$\sin(90^{\circ} - \theta)=\cos\theta$

Thus, for $\sin(90^{\circ} - x)$ comparing , we have,

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We get,

$\sin(90^{\circ} - x)=\cos x=\frac{1}{3}$

Thus, $\sin(90^{\circ} - x)=\frac{1}{3}$

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