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garik1379 [7]
3 years ago
9

What is the slope of the line represented by the equation below?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0
-2/3 is the slope because the equation is y=mx+b where m is the slope. not x. SO it is -2/3
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Multi step equation 12 threw 14 pls
slega [8]

The computation of the equation shows that the answers will be:

12. 340 units

13. 2(270) + (2 × x) = 690

14. x = 5

<h3>How to compute the equations?</h3>

12. The first equation that's given will be:

(13.50 × x) - (3.65 × x) = 3349

13.50x - 3.65x = 3349

9.85x = 3349

x = 3349/9.85

x = 340

The number to break even is 340 units

13. The equation that can be used to find the perimeter will be:

2(270) + (2 × x) = 690

540 + 2x = 690

2x = 690 - 540

2x = 150

x = 150/2 = 75

14. x + x + 2 + 8 = 20

2x + 10 = 20

2x = 20 - 10

2x = 10

x = 10/2

x = 5

Learn more about equations on:

brainly.com/question/2972832

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4 0
1 year ago
Read 2 more answers
What is the slope of the line that passes through the points (–20, 18) and (30, 14)?
natali 33 [55]
The slope of the line that passes through the points (-20,18) and (30,14) is

m (slope) =  -2/25
5 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINIEST!!
Vikki [24]

In order to prove that this quadrilateral is a parallelogram, we need to get the opposite sides to be parallel.

The answer would be D because it shows 2 triangles to be equal. If they are equal then they must have corresponding sides.

5 0
3 years ago
Which set of side lengths form a right triangle?
vova2212 [387]

Answer:

 Answer is 7cm,8cm,10cm

Step-by-step explanation:

A^2+B^2=C^2

6 0
3 years ago
Read 2 more answers
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
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