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GarryVolchara [31]
3 years ago
10

What is (16+10)-1+13x5=

Mathematics
2 answers:
Mariana [72]3 years ago
8 0
(16+10)-1+13*5
26-1+65
25+65
90
Dominik [7]3 years ago
5 0
Break it down....so
1. 16+10
=26-1
= 25

2. 13×5 =65
ANSWER =65+25
=90


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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

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Step-by-step explanation:

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Step-by-step explanation:

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Given a line passes through point (5,8) and the origin, find the equation of the line.<br> y=
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Answer:

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Step-by-step explanation:

I'm assuming that they're asking for the equation in point-slope form.

The formula is y=mx+b where:

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However, the y intercept is just (0,0) so b = 0

To find the slope we already have 2 given points: (0,0) and (5,8)

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Substitute the slope & y intercept in the formula:

y = 8/5x

Let me know if I'm wrong!!

6 0
2 years ago
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-y-4=4x<br> put in y=mx+b
marishachu [46]

-y-4=4x\\ \\ -y=4x+4\\ \\ y=-4x-4

<h3>First part of the problem:</h3><h3>-y - 4 = 4x</h3><h3>    + 4   + 4</h3><h3>-y + 0 = 4x + 4</h3><h3>      -y = 4x + 4</h3><h3 />

Hope this helps!

3 0
3 years ago
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