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12345 [234]
3 years ago
11

Ethan burns 650 calories when he runs for 1 hour. Soppose he runs 5 hours in one week

Mathematics
1 answer:
alex41 [277]3 years ago
3 0
650 x 5=3250 calories
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Describe the solution of the equation x^2+7x+2=0
yarga [219]
This is a quadratic equation with a general equation of ax^2 + bx + c.
The quadratic formula can help to get the roots of the equation. We know the highest degree of that equation is 2; so there will be also two roots.
The quadratic formula is
x = [-b ± √(b^2 - 4ac)] / 2a

With a = 1, b = 7, c = 2,
x = {-7 ± √[(7)^2 - 4(1)(2)]} / 2(1) = (-7 ± √41) / 2

So the two roots are
x1 = (-7 + √41) / 2 = -0.2984
x2 = (-7 - √41) / 2 = 0.2984

This is also another way of factorizing the equation
(x + 0.2984)(x + 0.2984) = x^2 + 7x + 2
4 0
3 years ago
Determine when the rational expression below is equal to zero ?
Airida [17]
It would be negative
8 0
3 years ago
Read 2 more answers
Mrs. DeMarco wants to estimate the height of her garage
valkas [14]

Answer:

length of baseball bat.

Step-by-step explanation:

she can measure the bat and times by how many times she could fit the bat there u know

6 0
3 years ago
What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

=(x+a)(x+b)

now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

k=a+b

ab=15

we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

k=-16

At (1\times 15):

k=a+b

we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

k=3+5

k=8

So, values of k are

k=-16,k=-8,k=8,k=16

6 0
3 years ago
A research company desires to know the mean consumption of meat per week among people over age 23. A sample of 164 people over a
Elan Coil [88]

Answer:

The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{0.7}{\sqrt{164}} = 0.07

The lower end of the interval is the mean subtracted by M. So it is 4.1 - 0.07 = 4.03 pounds

The upper end of the interval is the mean added to M. So it is 4.1 + 0.07 = 4.17 pounds

Rounded to one decimal place

The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.

8 0
3 years ago
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