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Valentin [98]
3 years ago
11

Find the sum of the finite sequence: 4, 2, 0, -2, - 4. A12 B0 C1 D4.

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

b.) 0

Step-by-step explanation:

i just took the test

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Solve for v in terms of s, t, u, and w.<br> wv=uts<br><br> v=___
laiz [17]

wv=uts\implies v=\frac{uts}{w}

we needed to eliminate w, do so by diving both sides by w and obtain the above result :)

Hope this helps.

8 0
2 years ago
Which of the following have two congruent parallel bases?
Andre45 [30]
Cylinder and prism.
7 0
3 years ago
The United States has a total area of 3,796,742 square miles.
Dvinal [7]

Answer:

4 * 10^6

Step-by-step explanation:

3,796,742 is about 4,000,000

4 * 10^? = 4,000,000

4 to 4,000,000 is an extra 6 zeroes

? = 6

4 * 10^6

4 0
2 years ago
Sally Jones had a policy with a $250 deductible which paid 80% of her covered charges less
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Answer:

50,,

Step-by-step explanation:

so you take 80percent of 250,, and deduct from medical expenses which becomes 50

4 0
3 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
3 years ago
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