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3 years ago

11

Find the sum of the finite sequence: 4, 2, 0, -2, - 4. A12 B0 C1 D4.

1 answer:

Finger [1]3 years ago

6 0

Answer:

b.) 0

Step-by-step explanation:

i just took the test

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What is the expanded form of the decimal 444.3? A) (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 10 ) B) (4 x 100) + (4 x 10) + (4 x 1

Tpy6a [65]

444.3 = (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 /10 )

Answer

A. (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 /10 )

6 0

3 years ago

Read 2 more answers

Whats 28 11/14 in simplest form

damaskus [11]

Mixed # x denominator + numerator = imp. Fraction

28 x 14 = 392 + 11 = 203

203/14 = 29/2 = 14.5

5 0

3 years ago

Read 2 more answers

Algebra:please answer #1 and show work

Novay_Z [31]

So 12 mins to 600 feet
35 mins=1900 feet
find the slope which is change in top over change in bottom (aka slope) so to find do
(y1-y2)/(x1-x2)
we want, per minute, so put the time as x1 and x2
x1=12
y1=600
x2=35
y2=1900
subsitutte
(600-1900)/(12-35)=-1300/-23=56.5 per minute
the answe ris 56.5 feet per minute or the last answer

4 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago

Got them.... I think the war is finally over..

lisabon 2012 [21]

Answer:

LOL THAT CAT POOR CAT

Step-by-step explanation:

nothing to see here

7 0

3 years ago