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stepan [7]
3 years ago
5

How can you describe a ratio as a fraction?

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
Let's say the ratio is 3:4. It could be written as 3/4
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Find the arc length of the partial circle.
nalin [4]

Answer:

1/2 pi

Step-by-step explanation:

This is 1/4 of a circle

Find the  circumference and multiply by 1/4

1/4 C

1/4 ( 2*pi*r)  where r is the radius

The radius is 1

1/2 pi*1

1/2 pi

7 0
3 years ago
Read 2 more answers
Seventy percent of the 100 students in middle school cafeteria bought their lunch sone of the students that brought there own lu
gogolik [260]
So we solve for each
70% of 100=70
students who didn't buy lunch=100-70=30

some of the 70 left so that the students who bought lunch, are 60% of those who are left
we know that the students who didn't buy lunch didn't change number so therefor
100% of students left-60%=40%= students that didn't buy lunch=30 so
40%=30
20%=15
100%=75
there were 75 students lfet in the cafeteria
3 0
3 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
A runner runs a distance of 450 metres in a time of 50 seconds. What is his average speed?
vekshin1

Answer:

0.279 miles / 0.449 km

Step-by-step explanation:

convert the meters into miles/kilometers to get your answer

4 0
2 years ago
Solve the system below by substitution. Give your answer as an ordered pair.
bearhunter [10]
Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
x=-4

y=6(-4)+23
y=-24+23
y=-1

The answer is (-4,-1)

Hopefully this helps!
6 0
3 years ago
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