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luda_lava [24]
3 years ago
15

You have been hired by an educational software company to create a program that automatically calculates the sum of each place-v

alue of two numbers. You can assume that the user of this program will only enter positive whole numbers greater than zero and less than 10,000.

Computers and Technology
1 answer:
Vinvika [58]3 years ago
4 0

Hi, you haven't provided the programing language, therefore, we will use python but you can extend it to any programing language by reading the code and the explanation.

Answer:

n1 = int(input("First numeber: "))

n2 = int(input("Second numeber: "))

for i in range(5):

   r1 = n1%10

   r2 = n2%10

   print(r1+r2)

   n1 = n1//10

   n2 = n2//10

 

Explanation:

  1. First, we ask for the user input n1 and n2
  2. We create a for-loop to calculate the sum of each place-value of two numbers
  3. We obtain the last number in n1 by using the mod operator (%) an the number ten this way we can always take the last value, we make the same for n2
  4. Then we print the result of adding the last two numbers (place value)
  5. Finally, we get rid of the last value and overwrite n1 and n2 to continue with the process

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Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

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Random rand = new Random();

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// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

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//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

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//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

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//Declaring local variables

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/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

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*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

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// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

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for (int i = 0; i < nos.length; i++) {

// Finding minimum element

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double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

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How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

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