Answer:
#include<iostream>
#include<cmath>
#include <ctime>
using namespace std;
int main()
{
time_t t = time(NULL);
tm* timePtr = localtime(&t);
cout << "seconds= " << (timePtr->tm_sec) << endl;
cout << "minutes = " << (timePtr->tm_min) << endl;
cout << "hours = " << (timePtr->tm_hour) << endl;
cout << "day of month = " << (timePtr->tm_mday) << endl;
cout << "month of year = " << (timePtr->tm_mon)+1 << endl;
cout << "year = " << (timePtr->tm_year)+1900 << endl;
cout << "weekday = " << (timePtr->tm_wday )<< endl;
cout << "day of year = " << (timePtr->tm_yday )<< endl;
cout << "daylight savings = " <<(timePtr->tm_isdst )<< endl;
cout << endl;
cout << endl;
cout << "Date " <<(timePtr->tm_mday)<<"/"<< (timePtr->tm_mon)+1 <<"/"<< (timePtr->tm_year)+1900<< endl;
cout << "Time " << (timePtr->tm_hour)<<":"<< (timePtr->tm_min)<<":"<< (timePtr->tm_sec) << endl;
return 0;
}
Explanation:
I'm almost certain it's D. I hope I'm right
Answer:
FALSE.
Explanation:
Susan remains in control of the corporation's stock statements. this would have to identify different product products and raise production costs for the plant. to keep comfortable, build a spreadsheet then select the Research Software of the following application.
She has to use that search feature to locate the identical similarity to such the product object, such that the range lookup value is set to FALSE.
Answer: Provided in the explanation section
Explanation:
The Question says;
Identify a logical operation (along
with a corresponding mask) that, when
applied to an input string of 8 bits,
produces an output string of all 0s if and
only if the input string is 10000001.
The Answer (Explanation):
XOR, exclusive OR only gives 1 when both the bits are different.
So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND
with 00000000 would also give 0,
but it would give 0 with all the inputs, not just 10000001.
Cheers i hope this helped !!
