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Wittaler [7]
3 years ago
13

(16x3 + 2x2) − 4x3 =

Mathematics
2 answers:
zimovet [89]3 years ago
7 0
Your answer would be 2x^2(6x+1)
kirill [66]3 years ago
4 0
16x^3+2x^2-4x^3

12x^3+2x^2

2x^2(6x+1)
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Study the Proof: Give the reasons for the missing reason. List the number and then state the reason.
joja [24]
1) Given
2) Adding segments AB and BC together gives AC (Addition postulate, not too sure about the terminology) 
3) Segment Addition postulate 
4) Segment Addition postulate(Knowing that AC=BD, the distance between BC and CD add up to BD, shown in #3. AB and BC add together to give AC) 
5) Subtraction property of Equality 

Hope I helped :) 
6 0
4 years ago
A number decreased by half of the number is four. What is the number?
MrRa [10]

Answer:

four is the right answer i think

4 0
3 years ago
Read 2 more answers
4/9 as decimal show your work
Fed [463]
    4/9 

= 0.44444444

= Rounded to 0.44

The correct answer is 0.44
4 0
4 years ago
Read 2 more answers
Point (-5,2) is reflected over the y axis. Where is the new point located?
umka21 [38]
The new point is (5,2)
8 0
4 years ago
5x - y + z = -6<br> 2x + 7y + 3z = 8<br> x + 2z = 6
BabaBlast [244]

Answer:

Step-by-step explanation:

The system of equations given are:

 

 5x - y + z = -6   ------------- i

 2x + 7y + 3z = 8  ---------- ii

  x + 2z = 6 ----------------- iii

Let us deal with equation i and ii first since they have 3 variables x, y and z;

      5x - y + z = -6                 x 7

       2x + 7y + 3z = 8            x 1

    35x  - 7y + 7z  = -42   ----  iv

      2x  + 7y + 3z  = 8       ---- v

Add equation iv and v;

    37x + 10z  = -34 ------vi

So, let us solve equation vi and iii:

               x + 2z = 6 - ---------- iii   x 10

               37x + 10z  = -34  --- iv  x 2

    10x + 20z   = 60         vi

     74x + 20z  = -68        vii

Subtract vi  - vii;

      -64x  = 128

          x  = -2

So;    put x  = -2 into iii;

           x + 2z  = 6

           -2 + 2z  = 6

            2z  = 6 + 2  = 8

           z  = 4

Put x  = -2 and z = 4 into equation i;

  5(-2) - y + 4  =  - 6

   -10 -y  +4  = -6

       -6  - y  = -6

             -y  = 0

              y  = 0

5 0
3 years ago
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