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Ivenika [448]
4 years ago
15

I have a different number of kids & can't seem ton find the correct numbers

Mathematics
1 answer:
bija089 [108]4 years ago
5 0
<h3>Answer: </h3><h3>Fred has <u>20 students</u> and Lee has <u>22 students</u></h3>

=============================================================

Work Shown:

L = number of students in Lee's class

F = number of students in Fred's class

Lee has 1.1 times as many students compared to Fred

This means we have this equation

L = 1.1F

Whatever the value of F is, we multiply that by 1.1 to get the value of L

The two amounts L and F add to 42 total students

L+F = 42

1.1F + F = 42 .... replace L with 1.1F

2.1F = 42

F = 42/(2.1)

F = 20 .... Fred has 20 students

L = 1.1*F

L = 1.1*20

L = 22 .... Lee has 22 students

------------

Check:

L+F = 22+20 = 42

this confirms the answer

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Micheal has 5^(2) boxes. There are 5^1 of apples in each box. When empty, a box weighs 5^-2 kg. What is the total weight of Mich
Orlov [11]

Answer: 1 Kilogram.

Step-by-step explanation:

You know that the weight of one box is 5^{-2} kilograms.

You also know that Micheal has 5^2 boxes.

If you want to know the total weight of Micheal's boxes when empty, you need to multiply the weight of one box by the total number of boxes that Micheal has.

You need to remember the Product of powers property:

(a^m)(a^n)=a^{(m+n)}

Then:

Total\ weight=(5^{-2}\ Kg)(5^2\ Kg)\\\\Total\ weight=5^{(-2+2)}\ Kg\\\\Total\ weight=5^0\ Kg

Remember that:

a^0=1

Then, the result is:

Total\ weight=1\ Kg

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D-5x-24%3D0" id="TexFormula1" title="x^{2}-5x-24=0" alt="x^{2}-5x-24=0" align="absmi
mars1129 [50]

Answer:

x=8,\:x=-3

Step-by-step explanation:

x^2-5x-24=0\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\mathrm{For\:}\quad a=1,\:b=-5,\:c=-24:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\left(-24\right)}}{2\cdot \:1}\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\x=8,\:x=-3=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:1\cdot \:24}}{2\cdot \:1}\\5+\sqrt{\left(-5\right)^2+4\cdot \:1\cdot \:24}\\5+\sqrt{121}\\=\frac{5+\sqrt{121}}{2}\\=\frac{5+11}{2}\\=\frac{16}{2}\\=8\\\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:1\cdot \left(-24\right)}}{2\cdot \:1}\\=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:1\cdot \:24}}{2\cdot \:1}\\5-\sqrt{\left(-5\right)^2+4\cdot \:1\cdot \:24}\\\left(-5\right)^2\\=25\\4\cdot \:1\cdot \:24\\=96\\=5+\sqrt{25+96}\\

\frac{5-\sqrt{121}}{2\cdot \:1}\\\frac{5-11}{2}\\=-\frac{6}{2}\\=-3\\

4 0
4 years ago
1. Solve the problem [(–7 + 2) + 4] – 3 = ?
Anna11 [10]

For number 3 it is D


4 0
3 years ago
How do I get the answer I’m confused
beks73 [17]
Yeahhhh bippity boop
5 0
3 years ago
Which of the following options is an equivalent function to f(x) = 4(3)2x?
Step2247 [10]
The correct answer is:  [B]:  " f(x) = 4(9)ˣ" .
_________________________________________________
Note: 
__________________________________________________
Given:  "f(x) = 4* (3²)ˣ  '

Note that:  "(3²) = "(3*3) = 9;

So;  "4* (3²)ˣ " = 4*(9)ˣ ;

which is:  Answer choice:  [B]:  " f(x) = 4(9)ˣ " .
_______________________________________________________
5 0
4 years ago
Read 2 more answers
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