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Gemiola [76]
3 years ago
8

How to solve scientific notation numbers

Mathematics
1 answer:
Luba_88 [7]3 years ago
4 0

Look at the exponent and move the decimal that many places ( to the right for a positive number and to the left for a negative number)

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Can someone please help me with this ASAP‼️ Thank You
AVprozaik [17]

Let x = cost of the dishwasher.

The amounts the children are paying are:

Mark =20% = 1/5, so  1/5x

Sorin = 75

Raymond = 1/4x

Stephanie = 75

Kristin = 1/3x

Add them together:

x = 1/5x + 1/4x + 1/3x + 75 + 75

x - ( 1/5x + 1/4x + 1/3x ) = 150

Rewrite fractions with common denominator:

x - ( 12/60x + 15/60x + 20/60x ) = 150

60/60x - 47/60x = 150

13/60x = 150

x = 150/1 • 60/13

x = 9000/13

x = 692.31

The total cost of the dishwasher is $692.31

Now calculate the amount each child pays:

Mark = 1/5 x = 692.31/ 5 = $138.46

Sorin = $75.00

Raymond = 1/4 x = 692.31 / 4 = $173.08

Stephanie = $75.00

Kristin =  1/3 x = 692.31 / 3 = $230.77

5 0
3 years ago
Why is 6 1/2 equal to the square root of 6
Aleksandr-060686 [28]
Because It Can Be Simplified Many Ways
4 0
3 years ago
Read 2 more answers
What is midpoint 85 90?
monitta
The midpoint of 85 and 90 is 87
8 0
3 years ago
In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60
Olegator [25]

Answer:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

Step-by-step explanation:

Data provided

\bar X=7.38 represent the sample mean for the fuel efficiencies

\mu population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size  

Confidence interval

The formula for the confidence interval of the true mean is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom for this case is given by:

df=n-1=601-1=600

The Confidence level for this case is 0.95 or 95%, and the significance level \alpha=0.05 and \alpha/2 =0.025 and the critical value is given by t_{\alpha/2}=1.96

Replcing into the formula for the confidence interval is given by:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

8 0
3 years ago
Which of the following statements must be true about this diagram
serg [7]
A B D and F must be true
7 0
3 years ago
Read 2 more answers
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