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Oksanka [162]
3 years ago
11

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point-slope

Mathematics
1 answer:
lara [203]3 years ago
7 0

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

1) Find m(the slope of the equation):

Since the slope-intercept form is already given, then you can obtain the slope from it by using y = mx + b

m=5

2) Substitute the given point into the point-slope form y - y1 = m(x - x1)

y-(-13) = 5(x - (-2))

y + 13 = 5(x + 2)

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Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

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<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

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In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

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The tangent is given by the sine divided by the cosine, hence:

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More can be learned about trigonometric identities at brainly.com/question/24496175

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ANSWER:

#include <stdio.h>

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int NetPay(int hours);

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Answer:

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