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2 years ago

If one angle of a rhombus is 35°, what are the remaining three angles?

Mathematics

2 answers:

MissTica2 years ago

6 0

B, hope this helped! Have a blessed day(:

Andreyy892 years ago

5 0

<span>35, 145 and 145 degrees is the answer</span>

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Angela uses 7 1/2 inches each of 6 different colors of embroidery floss to make one friendship bracelet. each package of floss c

shusha [124]

26 feet * 12 inces per foot / 7.5 inches = 41.6, which is 41 full bracelets

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2 years ago

I really need help I don’t understand how to do this

krek1111 [17]

Answer:

Step-by-step explanation:

Remark

The way this is worded, it sounds like it is a horizontal distance. However by the marking it looks like they want the hypotenuse. Life can be very confusing sometimes.

The angle of the triangle that you need to know is the one on the right. The line of sight line is parallel to the base of the triangle. So the angle on the right is 8 degrees by the Z theorem.

Solution

Sin(8) = 1817 / x Multiply both sides by x

x*sin(8) = 1817 Divide by sin(8)

x = 1817/sin(8)

sin(8) = 0.1392

x = 1817/0.1392

x = 13055.7

Note

Watch how you do this. I would put it into your calculator as

1817

sin(8)

If you use the rounded answer I gave for sin(8), you might get it wrong. This is a big distance and you should just use the exact number you get for sin(8).

8 0

2 years ago

An online store sells specialty bags. They charge $8 for shipping and $21 per bag ordered.

stellarik [79]

Answer:

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Step-by-step explanation:

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2 years ago

BRAINLIEST <br> Solve for X. Round to the nearest tenth.

Schach [20]

Answer:

a=180-(45+37)

b=180-(9+24)

c=180-(42+64)

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7 0

1 year ago

Read 2 more answers

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

2 years ago

Read 2 more answers