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3 years ago

A circle is the collection of points in a plane that are the same distance from a given point in the plane.

Mathematics

1 answer:

RoseWind [281]3 years ago

6 0

Answer:

True - The above statement is true

A circle is the collection of points in a plane that are the same distance from a given point in the plane.

Step-by-step explanation:

A circle is the set of points in a plane that are a given distance from a given point in the plane. The given point is the center of the circle, and the given distance is the radius.
In other words; A circle is the set of points in a plane that are equidistant from a given center point. Therefore; the locus of points at a fixed distance, d, from the point, P is a circle with the given point P as its center and d as its radius.

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to find the average number of points per game a player scores use the formula points per game = total points/games. find the num

murzikaleks [220]

Okay so this is your equation; 17=221/x all you need to do is multiply 221 by 17 and you'll have your answer. I hope this helps!

6 0

3 years ago

In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

tangare [24]

Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$

The length cannot be negative, so CD=8 cm and

$CA=\sqrt{3}CD=8\sqrt{3}\ cm$

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

$AB=2CA=16\sqrt{3}\ cm$

By the Pythagorean theorem,

$BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm$

3 0

2 years ago

Find the set of outcomes that occur when we flip 3 coins and obtain at least two tails.

Vikentia [17]

First, I would show all the outcomes possible. To determine the number of the total outcomes, you use the formula: rⁿ, where r is the number of outcomes in 1 flip, and n is the number of lips. Thus, 2³ = 8 outcomes. These outcomes are:

1. HHH
2. TTT
3. HHT
4. HTT
5. HTH
6. THH
7. TTH
8. THT

From the given outcomes, there are 3 outcomes that has at least two tails. These are the ones in bold characters.

5 0

3 years ago

Plz show work so I can understand thc

Korvikt [17]

It will take two and half hours because if she moves 14 flowers every hour and there 35 left it will take her two hours to move 28 since 14+14 is 28 and it will take half that time to get from 28 to 35 because 35-28 is 7. So you have your two 14s which equal 2 hours and then a 7 which is 30 mins. i’m

8 0

3 years ago

Use the distributive property to write an expression that is equivalent to each given property.

Nadya [2.5K]

Answer:

-6x+12

-9+5a

7x+63

8y-4/5x-12

Step-by-step explanation:

To solve these all you have to do is take the number outside of the parenthesis and multiply them by each term.

-3(2x)-3(-4) All I did here was expand the problem to show what i mean by terms.

-6x+12

Do this for each problem.

0.1(-90)+0.1(50a)

-9+5a

-7(-x)-7(-9) For this one you are taking negatives times negatives so each answer will be positive.

7x+63

4/5(10y)+4/5(-x)+4/5(-15)

8y-4/5x-12

3 0

3 years ago