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3 years ago

14

A vegetable garden and a surrounding path are shaped like a square that together are 11 feet wide. The path is 2 feet wide. Fins

the total area of the veget garden and path.

1 answer:

kondaur [170]3 years ago

8 0

The area of a square is found by S^2 where S is the length of a side.

The garden and path are 11 feet wide, so the total area for both is 11^2 = 121 square feet.

The length of a side of just the garden would be 11 - 4 ( 2 feet of path on both sides) = 7 feet

The area of the garden would be 7^2 = 49 square feet.

the area of the path would be the total area minus the area of the garden: 121-49 = 72 square feet.

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a piece of land 120 ft by 240 ft contains a circular garden. surrounding the garden, there is a circular fence that is 20 ft in

damaskus [11]

the area of the piece of land that is not part of the garden is $28,486ft^2$ .

<u>Step-by-step explanation:</u>

Here we have , a piece of land 120 ft by 240 ft contains a circular garden. surrounding the garden, there is a circular fence that is 20 ft in diameter. We need to find what is the area of the piece of land that is not part of the garden . Let's find out:

Let's calculate area of land and circular garden , and in order to find the area of the piece of land that is not part of the garden we will subtract area of circular garden from land !

Area of Land:

Area of land is given by

⇒ $length(width)$

⇒ $120(240)$

⇒ $28,880ft^2$

Area of Garden:

Area of circular garden given by

⇒ $\pi r^2$

⇒ $\pi (\frac{D}{2})^2$

⇒ $\pi (\frac{20}{2})^2$

⇒ $\pi (10)^2$

⇒ $100\pi$

⇒ $100(3.14)$

⇒ $314ft^2$

Hence , the area of the piece of land that is not part of the garden is 28,880-314 = 28,486 . Therefore , the area of the piece of land that is not part of the garden is $28,486ft^2$ .

8 0

3 years ago

Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 )

kati45 [8]

Answer:

$y=\frac{1}{2}x-6$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope (m)</u>

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (2,-5) and (8,-2)

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{-2-(-5)}{8-2}\\=\frac{-2+5}{8-2}\\=\frac{3}{6}\\=\frac{1}{2}$

Therefore, the slope of the line is $\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{1}{2}x+b$

<u>2) Determine the y-intercept (b)</u>

$y=\frac{1}{2}x+b$

Plug in one of the given points and solve for b

$-5=\frac{1}{2}(2)+b\\-5=1+b$

Subtract 1 from both sides to isolate b

$-5-1=1+b-1\\-6=b$

Therefore, the y-intercept of the line is -6. Plug this back into $y=\frac{1}{2}x+b$ :

$y=\frac{1}{2}x+(-6)\\y=\frac{1}{2}x-6$

I hope this helps!

6 0

3 years ago

The can of corn shown is a right circular cylinder with a height of 11 cm. The volume of the can is 486 cubic centimeters. What

hammer [34]

SOLUTION

Since the can is a cylinder, we will use the formula for volume of a cylinder to solve the problem.

Volume of a cylinder is given as

$\begin{gathered} V=\pi r^2h \\ where\text{ r = radius = ?} \\ h=height=11cm \\ V=volume=486cm^3 \end{gathered}$

Applying we have

$\begin{gathered} V=\pi r^2h \\ 486=3.14\times r^2\times11 \\ 486=34.54r^2 \\ r^2=\frac{486}{34.54} \\ r=\sqrt{14.07064} \\ r=3.75108 \end{gathered}$

Hence the answer is 3.8, the second option is the answer

6 0

2 years ago

Find the product of the least common multiple (LCM) of $8$ and $6$ and the greatest common divisor (GCD) of $8$ and $6$. Please

krek1111 [17]

The lcm is 1 and the gcd is 2

7 0

3 years ago

Read 2 more answers

A company has a $150 budget to provide lunch for its 20 employees. The options are to provide either roast beef sandwiches, whic

Reptile [31]

Answer:

D.) The company cannot provide lunch for all 20 employees and use the entire budget because there is no solution to the system of equations r+t=20 and 5r+5t=150

Step-by-step explanation:

The given information says that the <em>total</em> amount of lunch bought should equal $150 when both options cost $5:

$5r+5t=150$

It also says that the food should feed <em>all</em> 20 employees:

$r+t=20$

This is now a system. Solve by substitution.

Solve the second equation for r. Use inverse operations to isolate the variable by subtracting t from both sides:

$r+t-t=20-t\\\\r=20-t$

Now insert this value of r into the first equation:

$5(20-t)+5t=150$

Simplify the equation. Use the distributive property:

$5(20)+5(-t)+5t=150\\\\100-5t+5t=150$

Cancel the terms:

$100\neq 150$

100 does not equal 150, so there is no solution to the system.

:Done

3 0

3 years ago