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brilliants [131]
2 years ago
8

What is the equation of the quadratic function shown in the graph?

Mathematics
1 answer:
Reil [10]2 years ago
3 0

Answer: f(x) = -2 (x+3) (x-1)

Step-by-step explanation: See Attachment

You might be interested in
What is the maximum value of the function f(x) = -x2 + 4?
xenn [34]

Answer:

-x2+4=-x=4-2=2

-x=2

x= -2

8 0
3 years ago
What is the value of x³ + y³ when x= 3 and y=4?​
lara31 [8.8K]
You do (3)*(3)*(3)= 27
Then you do (4)*(4)*(4)= 64
Now you add them 27*64= 1728

I know this is correct because I am doing the same thing in my math class.
Hope this helps. :)
5 0
3 years ago
Draw to show the regrouping add 63 and 9
Makovka662 [10]
72 because 63 + 9 is basically 9×8
7 0
3 years ago
Can someone please help me?
Lena [83]

Hey there!

We can solve systems two ways - substitution and elimination. It seems in this case that elimination is going to be easier.


Let's begin by multiplying the top equation by 3, and the bottom equation by 4:

3(5x - 4y = -24)

15x - 12y = -72


4(4x + 3y = 18)

16x + 12y = 72


Next, we'll add the two equations together to get rid of, or eliminate, the y variable and solve for the x variable:

(15x - 12y = -72) + (16x + 12y = 72)

31x = 0

x = 0


Next, we'll plug the value of the x variable into the top equation and solve for the y variable:

5(0) - 4y = -24

-4y = -24

y = 6


Therefore, x = 0 and y = 6.


Hope this helps!! :)

7 0
3 years ago
Jim decides to start a small nonprofit business of renting out motor scooters to help out his area residents. He puts in his own
Deffense [45]
First, find the expected number of scooters rented per month:

As the data is symmetrical, E(X) (the expected value) is the middle value. So, on average, 2.5 scooters should be taken per month.

His total costs were 5 * 3000 = $15,000

So, to break even, he needs to make $15,000.

He will be selling for 5 years, or 60 months.

As a result, he needs to make 15000/60 = $250/month

As he is selling 2.5 scooters on average, he needs to rent each for:

$250/2.5 = <u>$100/month</u>
6 0
4 years ago
Read 2 more answers
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