Answer:
J - Janeta's age M - mother's age
A) (J-5) = .2 * (M-5)
B) J = (1/3) * M
Subtracting 5 from both sides of B:
B) J -5 = (1/3)M -5
then we substitute the right side of this into the left side of A and we get
(1/3)M -5 = .2 M -1
.333333333333M -5 = .2M -1
.1111111111111111111M = 4
Mother's Age = 36
Janeta's Age = 12
Step-by-step explanation:
Let x= original savings
(x-1,600) - 2/5 (x-1,600) = 1/3x
(x-1,600) - 2/5 + 640 = 1/3x
(3/5)x - 960 = 1/3x
(3/5)x - (1/3)x = 960
(4/15)x = 960
(15/4)(4/15)x = (15/4) 960
x = 15* 240 (960/4 = 240)
x = $3,600 is his original savings
Check:
$3,600 - 1,600 = 2,000
(2/5)($2,000) = $800
2,000 - 800 = 1,200 left over
Answer:
2/3 hr
4/5hr
Step-by-step explanation:
to attain time in motion...divide the distance by the speed
*the quantities must be the same though
3x + 4 = 10..subtract 4 from both sides
3x = 6....subtraction property of equality
Alright! We know that the total number of students is 100%. So, if 65% of the students brought a hot lunch, in order to find how many students brought a packed lunch you subtract it from 100%:
[100 - 65] = 35
So 35% of the students brought a packed lunch. Now, in order to find the fraction of students you simply put 35% of students over the total percent of students (100%)"
[35/100]
Then you simply:
[35/100] ⇒ [7/20]
The answer is 7/20ths of the students brought a packed lunch.
More:
Decimal form - .35
Percentage form - 35%
