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3 years ago

Five years ago Janeta age was one_fifth of her mother'sage .Now she is one_third of her mother's age.Find their present ages?

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

Answer:

J - Janeta's age M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

B) J -5 = (1/3)M -5

then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Step-by-step explanation:

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Answer:

Reaches a maximum height of 235.00 feet in 3.75 seconds.

Step-by-step explanation:

The height of the boulder, h, in feet after t seconds is given by the function is given by :

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For maximum height, put $\dfrac{dh}{dt}=0$

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$\dfrac{d(-16t^2+120t+10)}{dt}=0\\\\-32t+120=0\\\\32t=120\\\\t=3.75\ s$

Put t = 3.75 in equation (1). So,

$h=-16(3.75)^2+120(3.75)+10\\\\h=235\ \text{feet}$

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Answer:

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Answer:

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