Five years ago Janeta age was one_fifth of her mother'sage .Now she is one_third of her mother's age.Find their present ages?
1 answer:
Answer:
J - Janeta's age M - mother's age
A) (J-5) = .2 * (M-5)
B) J = (1/3) * M
Subtracting 5 from both sides of B:
B) J -5 = (1/3)M -5
then we substitute the right side of this into the left side of A and we get
(1/3)M -5 = .2 M -1
.333333333333M -5 = .2M -1
.1111111111111111111M = 4
Mother's Age = 36
Janeta's Age = 12
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