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julia-pushkina [17]
3 years ago
10

Can someone help me one these two​

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

On the top problem:  Angle A and Angle B are a right angle so it equals 90 degrees.  If Angle B is 50 degrees that makes Angle A 40 degrees.  Angle A and Angle C is a straight line and equals 180 degrees so if Angle A equals 40 degrees that means Angle C equals 140 degrees.

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How do I solve 3+k/14=4
Sedaia [141]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 53}}}}}

Step-by-step explanation:

\bigstar{ \sf{   \:  \: \frac{3 + k}{14} = 4}}

\tt{Step \: 1 \: } : Do cross multiplication

\hookrightarrow{ \sf{3 + k = 4 \times 14}}

\tt{Step \: 2} : Multiply the numbers : 4 and 14

\hookrightarrow{ \sf{3 + k = 56}}

\tt{Step \: 3 \: } Move 3 to right hand side and change it's sign

\hookrightarrow{ \sf{k = 56 - 3}}

\tt{Step \: 4 \: } Subtract 3 from 56

\hookrightarrow{ \sf{k = 53}}

The value of k is 53

Hope I helped!

Best regards! :D

~TheAnimeGirl

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Guided Practice
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The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 3x + 5 and g(x) = x2. Find g(x) − f(x).
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Step-by-step explanation:

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Step-by-step explanation:

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