Answer:
A
Step-by-step explanation:
The Tangent-Secant Exterior Angle Measure Theorem states that if a tangent and a secant or two tangents/secants intersect outside of a circle, then the measure of the angle formed by them is half of the difference of the measures of its intercepted arcs. Basically, what that means here is that 
equals half of the difference of 
and the measure of the unlabeled arc.
First, we need to find the measure of the unlabeled arc, since we can't find without it. We know that the measure of the full arc formed by the circle is 
, so the measure of the unlabeled arc must be 
by the Arc Addition Postulate.
Now, we can find . Using all of the information known, we can solve for like this:
Hope this helps!
Answer:
The slope is 8 and the y intercept is 0
Step-by-step explanation:
The equation is written in slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = 8x+0
The slope is 8 and the y intercept is 0
20*.4= 8
(20 as the original price, .4 is 40% as a decimal)
20+8
(eight being 40% of 20)
$28 is the new price.
Answer:
51.96 mm² approximately
Step-by-step explanation:
the first thing you should know is that the area of a rectangle is base*height sin of (
the included angle i.e
Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°
<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>
Aparallelogram= bh sin of sin of the included angle
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately
