Deny develops a new version of Fortnite and becomes a

What is 76.3 rounded to the nearest whole number

MatroZZZ [7]

76.
If the number after the decimal is below five, you round down. If the number is above five, you round up. 76 is your answer.

6 0

3 years ago

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

8 0

3 years ago

Read 2 more answers

Recall that rational numbers are numbers that can be represented as the ratio, or fraction, of two integers. When expressed as d

Alenkasestr [34]

Answer:

1) $\frac{5}{-14}$ =0.3571428571 2) Terminating

Step-by-step explanation:

1st. To answer this question let's divide with long division algorithm 5 and -14.

0.3571428571

-14)50

42

---

80

-70

--

100

98

---

20

14

----

60

-56

---

40

28

--

120

-112

----

80

70

--

100

-98

--

2

5 (dividend) : -14 (divisor) $\frac{5}{-14}$

Long division (check below)

With the same two numbers -14 and 5 we can write in a Long Division

5) -14

- 2.8

5) -14

10

40

So $\frac{-14}{5}=-2.8$

2nd. Both are terminating ones for they have finite quantities of numbers. -2.8 and 0.3571428571, as we can see that these are rational numbers for they can be written as a/b, and b≠ 0.

$\frac{5}{-14}$ form.

$\frac{-14}{5}$ form.