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2 years ago

14

At the North Fair you earn 9 points for each bull's eye you hit, but you lose 7 points for each miss. After 25 tries, Linda has

33 points. How many hits did she have?
A) 14
B) 13
C) 12
D) 11

2 answers:

Juliette [100K]2 years ago

6 0

Linda had (B) 13 hits. 13*9 - 12*7 would equal 33.

kaheart [24]2 years ago

4 0

Answer:

B

Step-by-step explanation:

took the test :))))

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Please help me with this. Use the combination method of substitution to solve. Please show and explain work. Thanks.

Artemon [7]

Answer:

x = 25.35 (or 2129/84) and y = 4334.04 (or 121353/28)

Step-by-step explanation:

The given equations are set up and ready to go with substitution. Simply just plug in the first equation to the second equation as both are equal to y.

Step 1: Replace y in <em>y = 87x + 2129 </em>with <em>171x</em>

171x = 87x + 2129

Step 2: Subtract 87 x on both sides

84x = 2129

Step 3: Divide both sides by 84 to get x

x = 2129/84 or 25.35 (rounded)

To get y, simply plug in x into one of the 2 original equations. In this case, I will use the first equation:

y = 171 (25.35)

y = 121353/28 or 4334.04 (rounded)

You can check your work by plugging both solutions into the calculator and see if they equal each other. The values for these answers are solely based on the equations, so if you write the <em>equations </em>wrong themselves, then that means you have the values wrong as well.

6 0

2 years ago

Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1

jek_recluse [69]

Answer:

$S_{31}=71.3$

Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

$U_n=a_1+(n-1)d$

We were given that the 9th term is $17$ .

$\Rightarrow 17=a_1+(9-1)(-2.1)$

$\Rightarrow 17=a_1+(8)\times(-2.1)$

$\Rightarrow 17=a_1-\frac{84}{5}$

$\Rightarrow 17+\frac{84}{5}=a_1$

$\Rightarrow a_1=\frac{169}{5}$

The sum of the first n-terms is given by the formula,

$S_n=\frac{n}{2}(2a_1+(n-1)d)$

To find $S_{31}$ , we substitute $n=31$ , $a_1=\frac{169}{5}$ and $d=-2.1$ .

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})$

$\Rightarrow S_{31}=\frac{713}{10}$

$\Rightarrow S_{31}=71.3$

The correct answer is D

8 0

3 years ago

Read 2 more answers

Ill give you 28 points if you answer this!!

elena-14-01-66 [18.8K]

Answer:

D

Step-by-step explanation:

because youe last number is 90

6 0

2 years ago

The ABC Toy Company is creating two similar pieces for board game, as shown below. Find the value of y that makes the two pieces

Ira Lisetskai [31]

A shape that is similar to another shape will be enlarged by a scale factor.
Each corresponding sides should give the same scale factor

Side GI corresponds to side JL
Side GH corresponds to side JK
Side HI corresponds to side KL

The correspond sides whose length are given is
GH = 4 and JK = 8

Side JK is twice longer than GH

All the other sides of triangle JKL are twice longer than triangle GHI, so we want that the side JL to be twice of the sides GI

Side GI = 6
Side JL = 6 × 2 = 12

Answer: y = 12

8 0

2 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

2 years ago