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Alex73 [517]
4 years ago
15

#20 #21 and #22 please for 12 points thank you

Mathematics
1 answer:
ipn [44]4 years ago
5 0

Answer:

20. AD = DC

21. AM = 9

22. x = 4 , RS = 3

Step-by-step explanation:

* <em>Lets explain how to solve the problems</em>

20)

-<em> A mid-point is the point which divides a line segment into two equal</em>

<em>  parts in lengths</em>

∵ D is the mid-point of AC

∴ D divides segment AC into two equal parts in lengths

∴ <em>AD = DC</em>

21)

- <em>Line l is a segment bisector of AC at point M</em>

∵ Segment l bisects AC at M

∴ M is the mid point of AC

∴ AM = MC

∵ AM = y + 6

∵ MC = 4y - 3

∴ 4y - 3 = y + 6

- Subtract y from both sides

∴ 3y - 3 = 6

- Add 3 to both sides

∴ 3y = 9

- Divide both sides by 3

∴ y = 3

- <em>Substitute the value of y in AM to find its length</em>

∴ AM = 3 + 6 = 9

∴ <em>AM = 9</em>

22)

<em>- Points R, S, T are col-linear and S is between R and T</em>

∴ RT = RS + ST

∵ RS = 2x - 5

∵ ST = 3x + 2

∵ RT = 17

- <em>Substitute these value in the equation above</em>

∴ 2x - 5 + 3x + 2 = 17

- Add like terms in the left hand side

∴ 5x - 3 = 17

- Add 3 to both sides

∴ 5x = 20

- Divide both sides by 5

∴ x = 4

* <em>The value of x is 4</em>

- <em>Substitute the value of x in RS</em>

∴ RS = 2(4) - 5 = 8 - 5 = 3

∴<em> </em><em>The length of RS = 3</em>

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Which is a factor of the polynomial f(x) = 6x4 – 21x3 – 4x2 + 24x – 35?
QveST [7]
<span>I note that this problem starts out with "Which is a factor of ... "  This implies that you were given several answer choices.  If that's the case, it's unfortunate that you haven't shared them.

I thought I'd try finding roots of this function using synthetic division.  See below:

f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation.  Thanks.

Possible zeros of this poly are factors of 35:  plus or minus 1, plus or minus 5, plus or minus 7.  Use synthetic division; determine whether or not there is a non-zero remainder in each case.  If none of these work, form rational divisors from 35 and 6 and try them:  5/6, 7/6, 1/6, etc.

Provided that you have copied down the function 
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35  properly, this approach will eventually turn up 1 or 2 zeros of this poly.  Obviously it'd be much easier if you'd check out the possible answers given you with this problem.

By graphing this function, I found that the graph crosses the x-axis at 7/2.  There is another root.

Using synth. div. to check whether or not 7/2 is a root:

         ___________________________
7/2   /   6    -21    -4    24    -35
                   21      0   -14     35           
        ----------- ------------------------------
           6        0     -4    10       0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial.  Thus, (x-3.5), or (x-7/2), is a factor.

7 0
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