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balu736 [363]
4 years ago
11

First stage of embryogenesis​

Mathematics
2 answers:
Rufina [12.5K]4 years ago
8 0
The process of embryogenesis begins with an egg or ovum being fertilized by a sperm cell to form a zygote.
Kobotan [32]4 years ago
4 0

Answer:

SThe process of embryogenesis begins with an egg or ovum being fertilized by a sperm cell to form a zygote

Step-by-step explanation:

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Evaluate m-8 when m= 12
finlep [7]

Answer:

4

Step-by-step explanation:

For m = 12

m - 8 = 12 - 8 = 4

4 0
3 years ago
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Figure FGHIJK is a regular hexagon. Segment FK is located at F (1, 2) and K (4, 2). What is the perimeter of FGHIJK?a 14 units b
ohaa [14]

Answer:

  c.  18 units

Step-by-step explanation:

Points F and K are 3 units apart. (Both are on the horizontal line at y=2, so the segment length is the difference of x-coordinates: 4 -1 = 3.)

Points F and K are adjacent vertices of the hexagon, so the perimeter will be 6 times the length of KF: 6·(3 unit) = 18 units.

5 0
3 years ago
Read 2 more answers
Given: ∆DEK, DE = EK
zhannawk [14.2K]
KF= 8 units
m∠DEK = 88°
m∠DFE = 90°
7 0
4 years ago
I’m having trouble with this problem. Please help
iVinArrow [24]

The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is

\vec r(t) = \sin(t) \, \vec\imath + 4t^3 \, \vec\jmath + 5t \, \vec k

Differentiate twice with respect to time t to get the velocity and acceleration vectors, respectively:

\dfrac{d\vec r}{dt} = \vec v(t) = \cos(t) \,\vec\imath + 12t^2 \,\vec\jmath + 5 \,\vec k

\dfrac{d^2\vec r}{dt^2} = \dfrac{d\vec v}{dt} = \vec a(t) = -\sin(t) \,\vec\imath + 24t \,\vec\jmath

Then at t=3, the acceleration of the particle is

\vec a(3) = -\sin(3)\,\vec\imath + 72\,\vec\jmath

which most closely resembles the first choice.

4 0
2 years ago
Here ya go these are the ones i need help with :)
r-ruslan [8.4K]
1) Division Property Equality
8D = 56
first pass: Simplify by 8
\frac{8D}{8} = \frac{56}{8}
second pass: <span>Now divide the equals
</span>1D= 7
D =  \frac{7}{1}
\boxed{D = 7}

2) Addition Property of Equality
Z - 9 = 21
first pass: <span>Incognito on the left and numbers without incognito on the right, changing signs if they change sides.
</span>Z = 21 + 9
second pass: Do the addition
Z = 21 + 9
\boxed{Z = 30}
<span>
3) Subtraction </span>Property of Equality
B + 7 = 15
first pass: Incognito on the left and numbers without incognito on the right, changing signs if they change sides.
B = 15 - 7
second pass: Do the subtraction
B = 15 - 7
\boxed{B = 8}
<span>
4) Multiplication Property of Equality
</span>\frac{3}{7} C = 126
first pass: <span>Multiply the equalities by the inverse of the incognito, without the incognito
</span>( \frac{7}{3}) *\frac{3}{7} C = 126*( \frac{7}{3})
\frac{21}{21} C = \frac{882}{3}
second pass: <span>Cancel the same terms and divide the ratio.
</span>\frac{\diagup\!\!\!\!\!21}{\diagup\!\!\!\!\!21} C = \frac{882}{3}
C =  \frac{882}{3}
\boxed{C = 294}

5) Distributive Property
<span>first pass: We only evaluate what is in the parentheses first and then we solve it.
</span>7(A+13)
second pass: we just evaluate what’s in the parentheses first, then solve it. We have a distributive property, with the distributive property, we multiply the '7' first.
7*A + 7*13
7A + 91

Obs: <span>This question is not to find the value, only to show the distributive property.
</span>
<span>For better understanding and solve your question with equation with incognito, after the distributive property, equalize the terms to zero, then isolate the terms, putting numbers with incognito on the left and numbers without incognito on the right, changing the signal as they change sides. And then solve by finding the value of the incognito dividing the terms.
</span>7A + 91 = 0
7A = - 91
A =  \frac{-91}{7}
\boxed{A = - 13}
<span>

</span>
5 0
4 years ago
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