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Alex Ar [27]
3 years ago
8

i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money

that i have. (Hint: one is the other simplified)
Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

We know that the total number of coins is 17.

N of the coins are nickels, and the rest of the coins are dimes.

Then the number of dimes is given by the difference between the total number of coins and the number of nickels, thus, there are:

17 - N dimes.

Each nickel has a value of $0.05

each dime has a value of $0.10

Then if you have N nickels and (17 - N) dimes, the total amount of money that you have is:

$0.05*N + (17 - N)*$0.10

This is the first expression, the second one comes if we simplify this.

First, we expand the second term:

$0.05*N + 17*$0.10 - N*$0.10

Now we can take the common factor N to get:

N*($0.05 - $0.10) + $1.70 = $1.70 - $0.05*N

$1.70 - $0.05*N is the simplified expression.

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<h3>Given</h3>

72 blue, 42 red beads

beads are used to make identical necklaces

<h3>Find</h3>

(a) the greatest number of necklaces that can be made

(b) the number of each color bead in each necklace

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... necklaces = 6(12 blue + 7 red)

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(a) You can make up to 6 identical necklaces. 6 is the largest common factor of 72 and 42. If you were to try to make more, they could not be identical.

(b) Each necklace can consist of 12 blue and 7 red beads. These are the numbers obtained when the total bead count is divided into 6 equal groups.

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There are several ways you can find the GCF of two numbers. For small numbers, it is generally feasible to use your knowledge of multiplication tables and factors to choose the largest common factor of two numbers. You can also use Euclid's algorithm, which is to repeatedly compute

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Here, that looks like

... 72 mod 42 = 30

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... 30 mod 12 = 6

... 12 mod 6 = 0 . . . . . . . so 6 is the GCF

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Of course, you know that

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Your graphing calculator may have a function for computing the greatest common divisor (GCD), too. The TI-84 does, for example.

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