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viktelen [127]
3 years ago
10

What is 9/10 divided by 7/10

Mathematics
2 answers:
belka [17]3 years ago
4 0
It's 9/7 but you can try simplifying after that
Marina86 [1]3 years ago
3 0
The answer is: 0.01285714285
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How do solve this equation step by step
Kryger [21]

Answer: 15n³-105n²+2n+16/6n²-42n

Step-by-step explanation:

n+8/3n²-21n +5n/2

2(n+8)+5n(3n²-21n)/2(3n²-21n)

2n+16+15n³-105n²/6n²-42n

15n³-105n²+2n+16/6n²-42n

7 0
4 years ago
Solve 2(4x + 5) > 7x + 20.
choli [55]
2(4x+5)>7x+20  perform indicated multiplication on left side

8x+10>7x+20  subtract 7x from both sides

x+10>20  subtract 10 from both sides

x>10

or in interval notation, x=(10, +oo)
8 0
4 years ago
What is the sum of a geometric sequence 1, 3, 9, ... if there are 12 terms?
attashe74 [19]
We know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
<span>common ration r is equal to 3
number of terms n  is 12

The </span><span>Sum of geometric series is given by the formula
</span>Sum=a1*[1-r<span>^n]/[1-r]
</span>Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
<span>Sum=531440/2-----> 265720

the answer is
265720



</span>
4 0
4 years ago
A car is traveling at a speed of 55 miles per hour.you want to write an algebraic expression to show how far the car will travel
goblinko [34]
Speed=Distance/Time
So Distance=Speed X Time
Distance=55T
Where 55 is the Car's speed and it is constant(won't change) and T is the time which is the changing variable.
you can plug time values to know the distance traveled!
4 0
3 years ago
A jet airplane, departing on time and flying between two airports at an average speed of $540 mph, arrives eight minutes late. D
Leokris [45]
<h3>Answer:   3240 miles</h3>

========================================

Work Shown:

Convert the given speeds from "miles per hour" to "miles per minute"

540 mi/hr = (540 mi/hr)*(1 hr/60 min)

540 mi/hr = (540/60) (mi/min)

540 mi/hr = 9 mi/min

480 mi/hr = (480 mi/hr)*(1 hr/60 min)

480 mi/hr = (480/60) (mi/min)

480 mi/hr = 8 mi/min

---------------

Let,

  • d = distance between two airports
  • x = time in minutes it takes the plane to travel 9 mi/min
  • y = time in minutes it takes the plane to travel 8 mi/min

If the plane travels 9 mi/min, then,

distance = rate*time

d = 9*x

d/9 = x

x = d/9

Similarly if the plane travels 8 mi/min, then,

d = 8*y

d/8 = y

y = d/8

Subtract the time values y and x

y-x = d/8 - d/9

y-x = 9d/72 - 8d/72

y-x = (9d-8d)/72

y-x = d/72

This difference represents 45 minutes because 53 - 8 = 45. The 53 and 8 are from the fact the plane is late 53 minutes and 8 minutes.

In other words, y-x = 45, so d/72 = 45 which solves to d = 3240 when you multiply both sides by 72.

---------------------------------

Extra Info:

If d = 3240, then

x = d/9 = 3240/9 = 360

y = d/8 = 3240/8 = 405

So y-x = 405 - 360 = 45

If the plane travels 9 mi/min (aka 540 mph) then it spends 360 minutes (6 hours) doing so. If the plane travels 8 mi/min (480 mph) then it spends 405 minutes (6 hrs, 45 min) doing so. So this is a more detailed look at why the time gap is 45 minutes.

4 0
4 years ago
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