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3 years ago

A blanket is 4 feet wide. It is 3 times as long as it is wide. Find the perimeter and area of the blanket.

Mathematics

1 answer:

garri49 [273]3 years ago

3 0

Answer:

P: 32

A: 48

Step-by-step explanation:

(4+(4*3))*2=32

4*(4*3)=48

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ZA and ZB are complementary angles. If mZA = (2x + 10)° and m

fiasKO [112]

Answer:

∠ZB = 54°

Step-by-step explanation:

Given:

Pair of complementary angles

∠ZA = (2x + 10)° and m

∠ZB = (3x + 15)

Find:

Measure of ∠ZB

Computation:

complementary angles

a + b = 90°

∠ZA + ∠ZB = 90°

(2x + 10) + (3x + 15) = 90

5x + 25 = 90

x = 13

So,

∠ZB = (3x + 15)

∠ZB = 13(3) + 15

∠ZB = 54°

3 0

3 years ago

NEED HELP ASAP! Subtract. (4x^2+8x−2)−(2x^2−4x+3) Answer in standard form

AlekseyPX

$(4x^2+8x-2)-(2x^2-4x+3)\\\\=4x^2+8x-2-2x^2+4x-3\\\\=(4x^2-2x^2)+(8x+4x)+(-2-3)\\\\=\boxed{2x^2+12x-5}$

4 0

3 years ago

If you help me just explain it to me

love history [14]

Answer:

Step-by-step explanation:

lets find median 2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

now lets find the lower quartile median and upper quartile median

we don't include the median in the count, only use it to divide the data into the two parts,

2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

so lower quartile median is 4,

2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

while upper quartile median is 10

the box represents the range between the upper quartile median and lower quartile median, thus is should go from 4 to 10 with the middle line, representing the median at 8,

the whiskers represent the whole data range

thus, the answer is C

6 0

3 years ago

Please help meeeeeeeee

baherus [9]

1 second = 2 megabytes

$1\frac{1}{2}\ seconds=3\ megabytes$

2 seconds = 4 megabytes

Step-by-step explanation:

Given,

Time taken to download 5 megabytes = $2\frac{1}{2}=\frac{5}{2}$ seconds

$\frac{5}{2}\ seconds = 5\ megabytes$

Multiplying both sides by $\frac{2}{5}$ to find unit rate

$\frac{2}{5}*\frac{5}{2}\ second = \frac{2}{5}*5\\1\ second = 2\ megabytes$

1 second = 2 megabytes

$1\frac{1}{2}\seconds = \frac{3}{2}\ seconds$

$\frac{3}{2}\ seconds = \frac{3}{2}*2$

$\frac{3}{2}\ seconds = 3\ megabytes$

$1\frac{1}{2}\ seconds=3\ megabytes$

2 seconds = 2*2 megabytes

2 seconds = 4 megabytes

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

4 0

3 years ago

On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th

Schach [20]

Answer:

Average speed is 37.35 mi/h

Step-by-step explanation:

given data

leave = 34 minutes before

church distance = 12.0 miles

average speed first 17 minutes = 5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × $\frac{17}{60}$

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

remaining distance Average speed = $\frac{distance}{time}$

Average speed = $\frac{10.584}{\frac{17}{60}}$

Average speed is 37.35 mi/h

3 0

3 years ago