1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slava [35]
3 years ago
13

Jake’s Cameras purchased a digital camera at a wholesale cost of $80. They marked up the price 50 percent above the wholesale co

st to use as their selling price. After every month that the camera didn’t sell, the store reduced the selling price by 25 percent. After how many monthly price reductions did the price dip below the wholesale cost?
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
4 0

Answer:

AFTER 2 MONTHS

Step-by-step explanation:

Nesterboy [21]3 years ago
3 0

Answer:

2 months

Step-by-step explanation:

$80 x 0.5 = $40

$80 + $40 = $120

$120 * 0.25 = $30

1st month - $120-$30 = $90

2nd month - $90-$22.5 = $67.5

You might be interested in
Please help me with this question it is due :) question 4.
Lynna [10]

Answer:

I ha.te U bit.ch

Step-by-step explanation:

Also, do U like these images?

6 0
3 years ago
Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0
3 years ago
Simplify (7p)^3 please thanks!
Talja [164]

Answer:

how

Step-by-step explanation:

3 0
3 years ago
3. use the law of exponents to evaluate (1/x) ^ -n when x= 7 and n= 2
emmainna [20.7K]
D on both ...................
8 0
3 years ago
Whats the commisson of 660 in 10%
Sholpan [36]

Answer:

0,10×660=66

660-66= 594

6 0
3 years ago
Other questions:
  • How do you do this???
    8·1 answer
  • 3x - 8 - 15x = a(2 - x)
    5·1 answer
  • According to the U.S. Census Bureau, about 24% of residents of the United States aged 25 years or older have completed at least
    13·1 answer
  • Working together, machine J, machine K, and machine L can complete a job in 12 minutes. Working alone, machine J can complete a
    8·1 answer
  • Given: <SPT = <RQT, ST = RT Prove: PR = QS​
    9·1 answer
  • How do I solve this I need help??​
    7·1 answer
  • Please help I will mark brainliest
    12·1 answer
  • Ausbin decides to use khan academy
    14·2 answers
  • Y + z-y; use y = 1, and z=3
    6·2 answers
  • Javier is going to a water park with his little brother, Caden. Since Caden is only 4 feet tall, they check to see if he is tall
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!