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Lady_Fox [76]
3 years ago
10

In which of these figures appear to contain a set of lines that is neither parallel nor perpendicular?​

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

D

Step-by-step explanation:

The lines in A meet at a right angle (90°) so they are perpendicular.

The lines in B meet at a right angle (90°) so they are perpendicular.

The lines in C do not meet and appear to be parallel.

The lines in D meet at an angle that does not appear to be 90°, so they are neither perpendicular nor parallel.

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Does anyone know this answer??
-Dominant- [34]

Answer:

Obtuse

Step-by-step explanation:

One of the angles is above 90 degrees

8 0
3 years ago
Read 2 more answers
Evan typed 72 pages of notes one day. He typed 1 2 of the pages in the morning and 1 3 of the pages in the afternoon. He typed t
Korolek [52]

Answer:

60 pages

Step-by-step explanation:

Evan types a total of 72 pages a day.

In the morning he typed 1/2 pages or 72/2 = 36 pages.

In the afternoon he typed 1/3 pages or 72/3 = 24 pages.

Together, he typed 36 + 24 = 60 pages in the morning and afternoon.

7 0
2 years ago
Solve the polynomial inequality x^2-3x-10>0
djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0
2 years ago
Please I need help immediately ​
just olya [345]

Answer:

Step-by-step explanation:

4x+6<= -54

4x <= -60

x <= -15    [The point -15 is included, so it must be a solid dot]

----------------

5x + 7 > -18

5x > -25

x > -5     [The point -5 is NOT included, so it should be an empty dot.]

Solution C seems the best.

4 0
2 years ago
Struct quadrilaterals for measurements given belo
Ierofanga [76]
I’m just trynna get points
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