5x-3y=3 x+6y=60 elimination
1 answer:
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<u>Answer: </u>
Kyle gave 2/7th of his money to his wife and spent 3/5 of the remainder. If he had $300 left, the money had by Kyle at first is $1050
<u>Solution: </u>
Step 1:
Consider “x” as the money which Kyle had initially.
From question, Kyle gave 2/7th of his money to his wife. So the remaining money left with Kyle is given as,
----- eqn 1
Now the remaining money left with Kyle is 5/7th.Given that Kyle spent 3/5 of the remaining money.
Now the remaining money left with Kyle is given as
Now kyle is left with $300, which is 2/5th of the initial money x .
We get equation as
2x = 1500
x = 750
Now Kyle is left with 750$ which is 5/7th of the initial amount x.( by using eqn 1)
We get equation as
5x = 5250
x = 1050
So the amount had by Kyle at first is $1050