According to the model, the year will the population exceed 470 million is 2060
What is the first step to take?
The first step in this case is to use the model to compute the population figure in each year as shown below:
N = 3.21t + 277.3
Year 2020:
t=20
N = 3.21(20) + 277.3
N=341.50
Year 2025:
t=25
N = 3.21(25) + 277.3
N= 357.55
Year 2030:
t=30
N = 3.21(30) + 277.3
N=373.60
Year 2035:
t=35
N = 3.21(35) + 277.3
N= 389.65
Year 2060:
t=60
N = 3.21(60)+ 277.3
N= 469.90
Year 2065:
t=65
N = 3.21(65)+ 277.3
N= 485.95
Since all the years given do not give the correct year, let us equate the target population figure to the model and solve for t
470= 3.21t + 277.3
470-277.3=3.21t
192.70=3.21t
t=192.70/3.21
t=60.03(approximately 2060)
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Answer:
The number of child tickets sold was 75 and the number of adult tickets sold was 97
Step-by-step explanation:
<u><em>The correct question is</em></u>
At the movie theater child admission is $6.30 an adult admission is $9.60 on Wednesday 172 tickets were sold for a total sales of $1403.70 How many child tickets and adult tickets were sold that day?
Let
x ----> number of child tickets sold
y ----> number of adult tickets sold
we know that
----> equation A
-----> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both lines
Using a graphing tool
The intersection point is (75,97)
see the attached figure
therefore
The number of child tickets sold was 75 and the number of adult tickets sold was 97
f(x) = x²<span> - 5x + 1
f(-3) = (-3)</span>² - 5(-3) + 1
<span>
f(-3) = 25
</span>--------------------------------------------------<span>
Answer: f(-3) = 25 (Answer C)
</span>--------------------------------------------------
Answer:
There were 4 adults; including Mr. Torres
Step-by-step explanation:
- Each row in the stadium had 9 seats
- Mr. Torres sat by himself; he sat on a row with nobody else (no students, no adults)
- The arrangement of the students and the adults who sat with them on same row is: A S S S A S S S A
1 2 3 4 5 6 7 8 9
since 1 adult sat at each end of a/the row and each group of 3 students was seated between 2 adults.
So the total number of adults that were present = 3 + 1 = 4
No because 4=4.00000 and there is that much more than 4.00000 so 4.002 is more