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konstantin123 [22]
3 years ago
6

Question 2 of 10

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer: (4x−9)(3x+4)   D

Step-by-step explanation:

Factor 12x2−11x−36

12x2−11x−36

=(4x−9)(3x+4)

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Answer:

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Step-by-step explanation:

the pH of the solution is 5.74.

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3 years ago
If Michael and Imani add 18% tip to the bill what does their lunch cost in total
Musya8 [376]

Answer:

X + (0.18 * X)  

where X is the price of the bill without the tip

Step-by-step explanation:

The first thing you have to do is convert the percentage to a decimal value. For example, if it is 30%, its decimal value is 0.30. As simple as dividing that 300 by 100. Repeat the previous step with all the percentages you have to add.

In this case it is 18% therefore the decimal value will be 0.18. As we do not have the value of the account, we will call this value X .

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3 years ago
In how many ways can the letters in the word 'Combination' be arranged?
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3 years ago
A large truck has two fuel tanks, each with a capacity of 150 gallons. Tank 1 is half full, and Tank 2 is empty.
12345 [234]

Answer:

1) G(t) = 75 + \frac{23}{4}t\\

2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

Step-by-step explanation:

1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:

\frac{150}{2} = 75 gallons

Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:

5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}

Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:

G(t) = 75 + \frac{23}{4}t\\

2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have

G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons

After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

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3 years ago
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