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konstantin123 [22]
2 years ago
6

Question 2 of 10

Mathematics
1 answer:
mariarad [96]2 years ago
5 0

Answer: (4x−9)(3x+4)   D

Step-by-step explanation:

Factor 12x2−11x−36

12x2−11x−36

=(4x−9)(3x+4)

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Use synthetic division to solve (x^4 – 1) ÷ (x – 1). What is the quotient?
Alenkinab [10]
Quotient is:

{ x }^{ 3 }+{ x }^{ 2 }+x+1

Remainder: 0

Answer and workings in the attachment below.

8 0
3 years ago
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Solve the equation. Then check your solution. – two-fifths + a = One-fifth a. Three-fifths c. StartFraction 3 Over 10 EndFractio
Helga [31]

Answer:

A . a = 3/5

Step-by-step explanation:

- 2/5 + a = 1/5

Add 2/5 to each side

-2/5 + a + 2/5 = 1/5 + 2/5

a = 3/5

Therefore a = 3/5

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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6 0
3 years ago
There's a piece of a pyramid is a rectangle with a width of 4.6 cm and the length of the 9 cm. What is the height in centimeters
Dominik [7]

Answer:

6cm

Step-by-step explanation:

Given data

Width= 4.6cm

Length= 9cm

Volume= 82.8cm^3

The expression for the volume is given as

V= lwh/3

82.8= 9*4.6*h/3

cross multiply

82.8*3= 9*4.6*h

248.4= 41.4h

h= 248.4/41.4

h= 6cm

8 0
3 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
2 years ago
Read 2 more answers
A, B & C form a triangle where Z
malfutka [58]

Answer:

BC≈8,38

Step-by-step explanation:

AB=a

BC=c

CA=b

a²+b²=c²

3.3²+7.7²=c²

√70,18=√c²

c≈8,38

8 0
2 years ago
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