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inn [45]
3 years ago
8

4x^2 + 20 = 0; TAKING SQUARE ROOTS

Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

<u>x₁ = i√5</u>

<u>x₂ = -i√5</u>

Step-by-step explanation:

Let's solve the equation using square roots.

4X^2 + 20=0

x² + 5 = 0 (Dividing by 4 at both sides of the equation)

x² = -5 (Subtracting 5 at both sides of the equation)

√x² = √-5 (Square root to both sides of the equation, √-1 = i)

x = +/- i√5 ( (Roots of the solution)

<u>x₁ = i√5</u>

<u>x₂ = -i√5</u>

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Y = 4x - 3<br>y= 2x + 13​
Serggg [28]

Answer:

x = 9, y = 29 or (8,29)

Step-by-step explanation:

Set the equations equal to each other because they both equal y:

4x - 3 = 2x + 13

Combine like terms:

2x = 16

Divide by 2:

x = 8

Plug 8 into the x for both equations and see if the y is the same:

y = 4(8) - 3 = 32 - 3 = 29

y = 2(8) + 13 = 16 + 13 = 29

7 0
3 years ago
Investing is a game of chance. Suppose there is a 36% chance that a risky stock investment will end up in a total loss of your i
Sergio039 [100]

Answer: P(x ≥ 1) = 0.893

Step-by-step explanation:

We would assume a binomial distribution for the outcome of the investment. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 36% = 36/100 = 0.36

q = 1 - p = 1 - 0.36

q = 0.64

n = 5

Therefore,

P(x ≥ 1) = 1 - P(x = 0)

P(x = 0) = 5C0 × 0.36^0 × 0.64^(5 - 0)

P(x = 0) = 1 × 1 × 0.107

P(x = 0) = 0.107

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3 0
3 years ago
The speedy punt returner and the ferocious defensive player are headed straight toward each other. The punt returner is travelin
Svetach [21]

Answer:

2

Step-by-step explanation:

15+12=27

54 / 27 = 2

8 0
3 years ago
Write the following numbers in order of size.<br> Start with the smallest number.<br> -6, 6,-5,0,12
Scorpion4ik [409]

Answer:

-6,-5,0,6,12

Step-by-step explanation:

The negative numbers are obviously smaller than the positive ones :)

4 0
3 years ago
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Deserts advance linearly, in easily mappable patterns.<br><br><br> True <br> False
mario62 [17]
It is false that deserts advance linearly, in easily mappable patterns.
Deserts don't really have a pattern when they are advancing - there are so many ways they can do this. 
7 0
3 years ago
Read 2 more answers
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