Use the ratio test to determine whether the series is convergent or divergent.
2 answers:
Answer:
Option A is correct. since series is convergent.
Step-by-step explanation
nth term of the given series is given by
on simplifying it ,we get
which gives zero at n = infinity
since value of the limit of the ratio is less than 1
given series is convergent [ by ratio test ]
Answer:
a) Convergent by ratio test
Step-by-step explanation:
Given is the series
General term =
To use ratio test
Let us write n+1 th term
=
Find ratio of n+1th term to nth term
We find that here numerator has degree as 1 and denominator as 3
SInce numerator has more powers, it approaches infinity faster than numerator thus making ratio tend to 0 as n becomes large
Since ratio tends to 0, we have this series is convergent.
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Answer:
.416
Step-by-step explanation:
(-.04)^3=-.064
(-.064)-(-.04^2)(-3)
(-.064)-(.16)(-3)
(-.064)-(-.48)
.416
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Maybe give the questions?
Answer:
Step-by-step explanation:
The absolute value function prevents the expression from being a polynomial. The degree of 3 in y^3 is an odd number so that polynomial function will not be even.