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We use the attached graph
a. The maximum profit is the y value that is the value of P(x) that reaches maximum. From the graph the maximum value of P(x) is 675
So the maximum profit the florist will earn from selling bouquets = $675
b. Break even is the point where the profit p(x) becomes 0
From the graph we can see that P(x) =0 at x= -10 and x=20
x=-10 is invalid
So, break even after 20 one- dollar decreases
c. The interval of number of one dollar decreases is where the profit P(x) is greater than 0.
From the graph its very clear that the profit P(x) is greater than 0 in the interval 0 to 20.
So, The interval of number of one dollar decreases for which the florist makes a profit from celebration bouquet is (0, 20)
