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Liono4ka [1.6K]
3 years ago
10

Please i need it asp

Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer:

pass the code

Step-by-step explanation:

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Find the distance :
faltersainse [42]
1. You would do 45 × 3 = 135 miles
2. 630 ÷ 2 = 315. 630 + 315 = 945 miles
3. 54 × 11 = 594 miles

1. Time is distance ÷ speed, so 4760 ÷ 560 = 8 1/2hours
2. 27 ÷ 54 = 0.5 hours, or 30 minutes
3. 1748 ÷ 437 = 4 hours

I hope this helps!
4 0
3 years ago
EASY QUESTION WILL GIVE BRAINLIEST
Lesechka [4]

Answer:

29622 m^2

Step-by-step explanation:

SA = 2 ( lw+ wh+ lh)  where l = length  w = width  h = height

SA = 2 ( 81*75+ 75* 56+ 81*56)

     = 2 (6075+4200+4536)

      = 2(14811)

      29622

6 0
4 years ago
Read 2 more answers
What is the value of the expression 5y2 + 4x when x = 2.5 and y = 3?
LUCKY_DIMON [66]

Answer:

it is 55 the 2nd one

5(9)+10=55

4 0
3 years ago
Read 2 more answers
How does your model represent the problem?
Paha777 [63]

Answer:

the first equation is the total legs on one dog being added together with 2 other total dog legs. The second equation is the number of dogs multiplied by the total number of legs on one dog. Either way both equation show 3 dogs with 4 legs each.

8 0
3 years ago
15.
boyakko [2]

Explanation:

a)

{3 \choose 2} = \frac{3!}{2!(3-2)!} = \frac{6}{2*1} = 3

{3 \choose 1} = \frac{3!}{1!(3-1)!} = \frac{6}{1*2} = 3

b) First, we have that

{n \choose k} = \frac{n!}{k!(n-k)!}

On the other hand,

{n \choose n-k} = \frac{n!}{(n-k)!(n(n-k))!} = \frac{n!}{(n-k)!k!}

Therefore, both expressions are equal. This makes sense, because selecting k elements from a group of n is the same than specify which elements you will not select. In order to specify those elements you need to select the n-k elements that will not be selected. Hence, each time you are selecting k from n, you are also selecting n-k from n, and from that reason both combinatorial numbers are equal.

4 0
4 years ago
Read 2 more answers
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