1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
____ [38]
3 years ago
15

30 POINTS!

Mathematics
1 answer:
inessss [21]3 years ago
7 0
126,773,792,413,402 days
887,416,546,893,814 weeks
5.324499281363e16 seconds
4,225,793,080,446.733 months

You might be interested in
Which of the following best explains the value of Sine StartFraction pi Over 3 EndFraction on the unit circle below?
Sedbober [7]

Answer:

A.

Step-by-step explanation:

Happy studying! I got this right <3

8 0
3 years ago
Read 2 more answers
Can someone please help with this or explain how to do it. I'm not very sure where to begin ToT
larisa86 [58]

Answer:

d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Step-by-step explanation:

First, we find the greatest common factor of 12x^23y^40z^9 and 10x^78z^5.

We work on the numbers, then on x, then on y, then on z.

We start with the GCF of 12 and 10.

10 = 2 * 5

12 = 2 * 3 * 3

The only factor 10 and 12 have in common is 2, so the GCF of 12 and 10 is 2.

Now we work on x. We have x^23 and x^78.

x^23 has 23 factors of x.

x^78 has 78 factors of x.

Since x^23 and x^78 have both at least 23 factors of x, x^23 is the GCF of x.

Now we work on y.

There is y^40 in one term, but there is no y in the other term. There is no GCF for the y.

Now we work on z. The first term has z^9. the second term has z^5. They both have at least 5 factors of z, so the GCF of z is z^5.

Now we put all the parts of the GCF together, and the GCF of the two terms is

2x^23z^5

We use option d. to factor.

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(___a____ + ____b___)

We already have the GCF outside the parentheses. Now we need to figure out what goes inside the parentheses.

The terms that go in positions a and b are the terms that when multiplied by the GCF give you the original expression.

We now work on position a.

What do you multiply by 2x^23z^5 to get 12x^23y^40z^9?

Answer: 6y^40z^4

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + ____b___)

Now we do the same for position b.

What do you multiply by 2x^23z^5 to get 10x^78z^5?

Answer: 5x^55

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Answer: d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

5 0
3 years ago
What is the distance between the points (−7, −3) and (−7, −9) ?
MrRa [10]

Answer:

6 units

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which values are solutions 4x greater than or equal to 35
Mamont248 [21]

Answer:

\frac{5}{1/2}, 12, \frac{8}{3/4}, 10

Step-by-step explanation:

4x\geq 35

x \geq \frac{35}{4}

x \geq 8 \frac{3}{4}

so

\frac{5}{1/2} = 10

12

\frac{8}{3/4} = 10.66

and 10

Because saying 5 over 1/2 is saying 5 divided by 1/2 which is the same as saying 5 * 2

8 over 3/4 is 8 divided by 3/4 which is 8 * 1.33.

A fraction is division. If you mean 5 and 1/2 as well as 8 and 3/4 then remove 5 and 1/2 from the answer.

6 0
3 years ago
Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How
HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that \mu = 5.2r, in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

P(X \geq 1) = 1 - P(X = 0) = 0.99

Thus:

P(X = 0) = 1 - 0.99 = 0.01

We have that:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}

Then

e^{-5.2r} = 0.01

\ln{e^{-5.2r}} = \ln{0.01}

-5.2r = \ln{0.01}

r = -\frac{\ln{0.01}}{5.2}

r = 0.89

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0
3 years ago
Other questions:
  • What does 3cm by 7cm mean
    8·2 answers
  • one lap around the track is 1/4 mile.Jose wants to run 5 miles. How many times must he run around the track?
    6·2 answers
  • Find the area of the following: <br> -square whose sides are (x+1) in length
    5·2 answers
  • PLEASE HURRY<br> solve for x. <br> 3(x + 5) - 2(x + 2) =20 <br><br> 1.) 1<br> 2.) 9<br> 3.) 13
    12·1 answer
  • carlos made up a game where, in a deck of cards, the red cards (hearts and diamonds) are negative and the black cards (spades an
    15·2 answers
  • Factor completely 4xy + 9x + 24y + 54.
    13·2 answers
  • Evaluate the expression? (15+6) divided by 3 ?
    13·2 answers
  • Can anyone help please ?
    11·1 answer
  • What is the slope of the line that passes through the points (−4,−3) and (14,0)?
    12·1 answer
  • 6 = x/7 - 8 solve for x
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!