All categories

2 years ago

How do you do this? -5x+y=-3 3x-8y=24

2 answers:

6 0

$-5x+y=-3 \ \ \ |\times 8 \\
3x-8y=24 \\ \\
-40x+8y=-24 \\
\underline{3x-8y=24 \ \ \ \ \ \ \ } \\
-40x+3x=24-24 \\
-37x=0 \ \ \ |\div (-37) \\
x=0 \\ \\
3x-8y=24 \\
3 \times 0 -8y=24 \\
-8y=24 \ \ \ |\div (-8) \\
y=-3 \\ \\
\boxed{(x,y)=(0,-3)}$

qwelly [4]2 years ago

3 0

Where going to be solving this using the substitution method so to do that we need to first find are chunk like so add 5x to each side to your first equation to get
y=(-5x-3) now we are ready to solve now that we have are chunk, first we need to insert are chunk into the other equation like this
3x-8(-5x-3)=24 now we distribute like so 3x+40x+24=24 now we add like terms
43x+24=24 now was subtract 24 from each side like so 43x=0 now we divide by 43 0/43=0 so x=0 now we can find y by inserting are x like so
y=(-5*0-3) solve for the parentheses and that leaves us with are end answer of
$\left \{ {{y=-3} \atop {x=0}} \right.$ Enjoy!=)

You might be interested in

What adds to 1 and multiplies to 2

kicyunya [14]

-2 and 1.

Hope this helps!

3 0

3 years ago

Read 2 more answers

A tipping platform is a ramp used to unload trucks. How high is the end of an 100 foot ramp when it is tipped by a 30 degree ang

Naily [24]

According to the information given, the ramp would be 50 feet high. (However, that seems really high. Did you type your problem correctly?)

If you draw a picture, you will see that you can set up a cosine ratio to solve this problem. With a 30 degree angle of depression, the angle we are going to use 60 degrees.

We can set up the following equation:

cos(60) = x / 100
0.5 = x / 100
50 = x

6 0

3 years ago

Simplify (4x-8)/(-3x)*(12)/(12-6x)

zloy xaker [14]

$\dfrac{4x-8}{-3x}\cdot\dfrac{12}{12-6x}=\dfrac{4(x-2)}{-x}\cdot\dfrac{4}{-6(x-2)}=\dfrac{4}{-x}\cdot\dfrac{4}{-6}\\\\=\dfrac{2}{-x}\cdot\dfrac{4}{-3}=\dfrac{(2)(4)}{(-x)(-3)}=\dfrac{8}{3x}$

7 0

2 years ago

Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess

Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2$

4 0

3 years ago

Read 2 more answers

Help i need help with this 10x+16>6x+20

Mamont248 [21]

What does > mean?

10x + 16 ≥ 6x + 20

Subtract both sides by 16

10x ≥ 6x + 4

Subtract both sides by 6x

4x ≥ 4

Divide both sides by 4

x ≥ 1

I believe this is your answer good luck!!

<<<Emily>>>

4 0

3 years ago